ID:               24720
 Updated by:       [EMAIL PROTECTED]
 Reported By:      adrian at smartcall dot ro
-Status:           Open
+Status:           Feedback
-Bug Type:         MySQL related
+Bug Type:         MSSQL related
 Operating System: linux slackware
 PHP Version:      4.3.2
 New Comment:

Please try using this CVS snapshot:

  http://snaps.php.net/php4-STABLE-latest.tar.gz
 
For Windows:
 
  http://snaps.php.net/win32/php4-win32-STABLE-latest.zip

And give a complete example script, WITHOUT any 'include/require'
calls.



Previous Comments:
------------------------------------------------------------------------

[2003-07-19 14:48:53] adrian at smartcall dot ro

Description:
------------
I updated my php to php-4.3.2 on apache_1.3.27, I have mysql-3.23.57
and I also use freetds-0.61.
My php ./configure line is 
'./configure' '--prefix=/usr/local/misc/php'
'--with-apxs=/usr/local/misc/apache/bin/apxs'
'--with-mysql=/usr/local/misc/mysql'
'--with-sybase-ct=/usr/local/misc/freetds'  
All my scripts ( that before worked ) are giveing me the followig error
:
Warning: mysql_result(): supplied argument is not a valid MySQL result
resource 
mssql_fetch_row(): supplied argument is not a valid Sybase result
resource 

This error apears when no line maches the query !

In the first place I thought that is the freetds driver ... but I saw
that even on mysql i'm geting the same error.


Reproduce code:
---------------
 $msdb = mssql_connect("192.168.0.5", "web","webpass");
  mssql_select_db("DATABASE",$msdb);

  $result = mssql_query("SELECT DEALERS.PASS FROM DEALERS WHERE
DEALERS.DEALER='" . $_POST["DealerName"] . "'", $msdb);

  $msrow = mssql_fetch_row($result);

  if ( $msrow[0] != $_POST["DealerPass"] )
   { mssql_close($msdb);
     include("../include/error_message.html");
     exit();
   }


Expected result:
----------------
Warning: mssql_fetch_row(): supplied argument is not a valid Sybase
result resource in /home/www/default/dealer/check_dealer.php on line 7


Actual result:
--------------
In $msrow[0] I should have the password ( I have the password when
$_POST["DealerName"] matches one of the DEALERS.DEALER from DEALERS )
but if $_POST["DealerName"] can't be found in the table I'm getting
Warning: mysql_result(): supplied argument is not a valid MySQL result
resource 
I "echo("Result = ".$result);" and when I have a match I'm getting
"Result = Resource id #7" and when not a match I have "Result = 1". Is
this correct ? Before using php 4.3.2 I didn't faced this problem !


------------------------------------------------------------------------


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