ID: 41364
Updated by: [EMAIL PROTECTED]
Reported By: wimroffel at planet dot nl
-Status: Open
+Status: Bogus
Bug Type: Unknown/Other Function
Operating System: Windows XP
PHP Version: 5.2.2
New Comment:
This behaviour is undefined in all languages including PHP.
Previous Comments:
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[2007-05-11 13:11:44] wimroffel at planet dot nl
Description:
------------
When I have a loop
for($i=0; $i<$size;)
{ $myarr[$i][3] = $i++;
}
PHP will first take the assigned value, then increase $i and that use
the new $i to set the array. So the first loop will do:
$myarr[1][3]=0;
I come from PHP4 and there this worked correctly (first line
$myarr[0][3]=0;).
I am using XAMPP and as a consequence PHP 5.2.1. But I couldn't find
this in the bug database so I suppose it has not been solved.
Reproduce code:
---------------
$myarr = array();
$myarr[0] = array("A","B","C");
$myarr[1] = array("D","E","F");
$myarr[2] = array("G","H","I");
$size = sizeof($myarr);
echo "The size of myarr is ".$size."<br>";
for($i=0; $i<$size;)
{ $myarr[$i][3] = $i++;
}
for($i=0; $i<$size; $i++)
{ echo "Record ".$i." = ".$myarr[$i][3]."<br>";
}
echo "The size of the array is now ".sizeof($myarr);
Expected result:
----------------
The size of myarr is 3
Record 0 = 0
Record 1 = 1
Record 2 = 2
The size of the array is now 3
Actual result:
--------------
The size of myarr is 3
Record 0 =
Record 1 = 0
Record 2 = 1
The size of the array is now 4
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Edit this bug report at http://bugs.php.net/?id=41364&edit=1
