Edit report at http://bugs.php.net/bug.php?id=46034&edit=1
ID: 46034
Comment by: jimb at connectedsw dot com
Reported by: php at ryank dot net
Summary: php cli -d include_path only accepts first parameter
Status: Bogus
Type: Bug
Package: CGI related
Operating System: WinXP
PHP Version: 5.2.6
Block user comment: N
Private report: N
New Comment:
The bug is that 5.2 does not understand the use of apostrophes for
quoting. This was fixed in 5.3. Test case #5 below shows a workaround
for 5.2.
The problem reported by ryank is not a bug because his quoting was wrong
and so the semicolon was being interpreted as a statement separator.
Ryank could not use the quoting solutions recommended by the others
because the apostrophe didn't work for quoting in 5.2. Since ryank used
PHP 5.2 and kalle used 5.3, they were seeing different results.
To test this bug, I created a file named "test.php" and put the file in
C:\ftp.
Test case #1: This works in 5.2 and 5.3.
php -r "print ini_get('include_path');require_once('test.php');" -d
"include_path=C:\ftp"
Test case #2: This fails in 5.2 and 5.3, but that's correct because the
semicolon is a command separator:
php -r "print ini_get('include_path');require_once('test.php');" -d
"include_path=C:\tmp;C:\ftp"
Test case #3: This fails in 5.2 and works in 5.3. This shows that 5.2
can't handle single quotes:
php -r "print ini_get('include_path');require_once('test.php');" -d
"include_path='C:\ftp'"
Test case #4: This also fails in 5.2 and works in 5.3. However, the
reason is because 5.2 can't handle the single quotes.
php -r "print ini_get('include_path');require_once('test.php');" -d
"include_path='C:\tmp;C:\ftp'"
Test case #5: This works in both 5.2 and 5.3. It works around the 5.2
limitation.
php -r "print ini_get('include_path');require_once('test.php');" -d
"include_path=\"C:\tmp;C:\ftp\""
Previous Comments:
------------------------------------------------------------------------
[2008-10-24 15:43:58] j...@php.net
There's no bug here.
------------------------------------------------------------------------
[2008-10-03 06:36:59] ka...@php.net
Works fine for me:
C:\php\src\Release_TS>php -v
PHP 5.3.0alpha3-dev (cli) (built: Oct 2 2008 21:44:41)
Copyright (c) 1997-2008 The PHP Group
Zend Engine v2.3.0, Copyright (c) 1998-2008 Zend Technologies
C:\php\src\Release_TS>php -r "print ini_get('include_path');" -d
"include_path='
C:\test1.ini;C:\test2.ini'"
C:\test1.ini;C:\test2.ini
The Windows shell only likes the double quote sign, so therefore
"include_path='xxxx'" will work. but not 'include_path="xxxx"' (Will
cause a alert saying 'Invalid configuration directive')
------------------------------------------------------------------------
[2008-09-11 14:39:57] lbarn...@php.net
The quotes are "used" by your shell, just like those around the php
code.
-d "include_path=foo;bar" is passed as -d include_path=foo;bar to php.
You must enclose the quotes themselves, for example by using single
quotes: -d 'include_path="foo;bar"' (works on "classic" shells, but I
don't know how windows handles this)
------------------------------------------------------------------------
[2008-09-11 14:24:28] php at ryank dot net
Still having issues:
C:\>php -r "print ini_get('include_path');" -d
"include_path=c:\testing1;c:\testing2"
c:\testing1
C:\>php -r "print ini_get('include_path');" -d
"include_path=.;c:\testing1;c:\testing2"
.;c:\testing1;c:\testing2
------------------------------------------------------------------------
[2008-09-10 20:15:59] j...@php.net
You need to enclose all of it in quotes:
# php -d "include_path=some;path;here" ..
------------------------------------------------------------------------
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