Hi there everyone,
Is there a quick and easy (HAH :-) way of doing the following:
I have a DB and a table with id, date etc . now what I need is to create 3 years
of entries for the date in advance of the system going live (Rather than while they
use it - hard to explain why but necessary).
on 3/1/03 12:16 AM, Cameron at [EMAIL PROTECTED] appended the
following bits to my mbox:
> I'm new to this stuff, so you have to excuse me if I seem dense. I can't
> get MySQL base operation from PHP 4.22 under RedHat Linux 8.0. I get the
> following error when trying to use mysql_connect().
>
on 3/1/03 2:00 PM, Jeremy N.E. Proffitt at [EMAIL PROTECTED] appended
the following bits to my mbox:
>> What's wrong with PhpMyAdmin?
> It has to be HTML based, it can't install on the server.
Well, you can't administer MySQL with HTML pages. You need PHP pages that
generate HTML pages. PHPMyA
I have a website that is hosted by Yahoo! Web Hosting which supports PHP with MySQL.
The db is already created, so there's no problem there. The problem I am having is
knowing what code to write for my form entries so that the info entered by a user can
be sent to my db named "users" and then
I have a website that is hosted by Yahoo! Web Hosting which supports PHP with MySQL.
The db is already created, so there's no problem there. The problem I am having is
knowing what code to write for my form entries so that the info entered by a user can
be sent to my db named "users" and then
At 04:33 PM 3/1/2003 -0500, Jeremi Bergman wrote:
www.php.net/round
find the answer there, you will :-)
~kurth
Nevermind, I found the answer, and why it wasn't working. Now I was
wondering how I can format a number to be a currency? Like if
$totalprice = 14.343 have it print 14.34.
thanks
--
> Nevermind, I found the answer, and why it wasn't working. Now I was
> wondering how I can format a number to be a currency? Like if
> $totalprice = 14.343 have it print 14.34.
Number_format() or printf()
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your
Nevermind, I found the answer, and why it wasn't working. Now I was
wondering how I can format a number to be a currency? Like if
$totalprice = 14.343 have it print 14.34.
thanks
-Original Message-
From: Jeremi Bergman [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 01, 2003 2:13 PM
To
How can I redirect a user to a specific page if they are already
"authenticated"?
if ($SESSION_Authenticated) { //code here to redirect; }
thanks
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
It has to be HTML based, it can't install on the server.
- Original Message -
From: "Leif K-Brooks" <[EMAIL PROTECTED]>
To: "Jeremy N.E. Proffitt" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Friday, February 28, 2003 9:37 PM
Subject: Re: [PHP-DB] Creating MySQL Entry Forms
> What's
Paul Burney wrote:
> on 2/28/03 3:15 PM, Daniel Harik at [EMAIL PROTECTED] appended the
> following bits to my mbox:
>
>> Thank You for your reply, but the problem is that users may have many
>> photos, and i need to get only one, i use folllowing sql:
>> SELECT users.username, photos.file FROM u
Mark wrote:
>
> --- Daniel Harik <[EMAIL PROTECTED]> wrote:
>> > > Hello,
>> > >
>> > > I have 2 tables users table, that stores user info, and photos
>> table,
>> > > i want to select all users with one photo form photos table,
>> but i don't
>> > > want it to be photos * users = result.
>> > >
You might try getting the random number before the query.
-Original Message-
From: Rich Gray [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 01, 2003 8:37 PM
To: Frank Keessen; [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: [PHP-DB] RE: [PHP] Random not working?
> Hi All,
>
> I'm trying t
Thanks guys for the info; I will speak to my ISP!
Have a nice weekend!
Regards,
Frank
- Original Message -
From: "Rich Gray" <[EMAIL PROTECTED]>
To: "Frank Keessen" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Sunday, March 02, 2003 2:36 AM
Subject: [PHP-DB] RE: [P
> Hi All,
>
> I'm trying to get a random record each time this script runs;
> Only it's giving me everytime the first record back.. No random at all..
>
> // generate and execute query
> $query = "SELECT stedenid, naamstad, stadomschrijvk FROM steden
> ORDER BY RAND() LIMIT 1";
> $result = mysql_qu
This recent thread from the mysql list explains a lot about the
problem.
http://lists.mysql.com/cgi-ez/ezmlm-cgi?1:mss:15034
hth,
Doug
On Sat, 1 Mar 2003 12:24:57 +0100, Frank Keessen wrote:
>Hi All,
>
>I'm trying to get a random record each time this script runs; Only it's giving me
>everytim
Could you post your entire script to see what's wrong ?
-Message d'origine-
De : Cameron [mailto:[EMAIL PROTECTED]
Envoyé : samedi 1 mars 2003 6:17
À : [EMAIL PROTECTED]
Objet : [PHP-DB] undefined function: mysql_pconnect()
I'm new to this stuff, so you have to excuse me if I seem dense.
I'm new to this stuff, so you have to excuse me if I seem dense. I can't
get MySQL base operation from PHP 4.22 under RedHat Linux 8.0. I get the
following error when trying to use mysql_connect().
"Call to undefined function: mysql_pconnect()"
I don't have any other PHP running on the box, oth
Hi All,
I'm trying to get a random record each time this script runs; Only it's giving me
everytime the first record back.. No random at all..
// generate and execute query
$query = "SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT
1";
$result = mysql_query($query) or
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