On Friday 12 December 2003 10:24 am, Martin Marques wrote:
> > That is fine and all, but my original example was just an example of the
> > non functionality of pg_result_error(), not how to handle errors when a
> > query fails.
> > But for arguement sake, lets use your example in some dummy code[0
One thing I might suggest is to queue up your inserts, then use the extended
insert syntax to populate several records at once in a single INSERT instead
of 12 separate ones. I believe you can alter the /etc/my.cnf file to play
more 'nice' as far as priorities and memory, but I've never touched it
Hi
I´m using a connection using php 4.3.3 with sql server ... and i´m having a error
message :
mssql error: [: Connection error to server '192.0.0.6\binotto' with user 'LUA'] ..
The user 'LUA' is the dbowner ...
anyone can help me???
Sorry my bad english ...
Liana Cristine Leopold
El Vie 12 Dic 2003 11:19, Gerard Samuel escribió:
> Im going to CC this to the PostgreSQL list also.
>
> On Friday 12 December 2003 06:44 am, Martin Marques wrote:
> > El Vie 12 Dic 2003 00:09, Gerard Samuel escribió:
> > > What good is this function?
> > > A quick example of the wall Im running in
Im going to CC this to the PostgreSQL list also.
On Friday 12 December 2003 06:44 am, Martin Marques wrote:
> El Vie 12 Dic 2003 00:09, Gerard Samuel escribió:
> > What good is this function?
> > A quick example of the wall Im running into ->
> > $sql = 'INSERT INTO .';
> > $result = pg_query(
$keywords = str_replace(' ','%',$keywords);
select * from table where data like "%keywords%";
-Original Message-
From: Hadi [mailto:[EMAIL PROTECTED]
Sent: 12 December 2003 13:21
To: [EMAIL PROTECTED]
Subject: [PHP-DB] anyone trickier than 'LIKE' ?
Hi all,
I have this data (eg.) "..
I have this data (eg.) "..big fat buddy..." on the
database . If
a person enter "big buddy" in the search form , the "...big fat
buddy." data will not be found . Any suggestion ?
select * from table where data like "%keywords%";
You can break up the search terms into words
Hi all,
I have this data (eg.) "..big fat buddy..." on the database . If
a person enter "big buddy" in the search form , the "...big fat
buddy." data will not be found . Any suggestion ?
Thanks in advance.
select * from table where data like "%keywords%";
--
PHP Database
On Friday 12 December 2003 20:15, JeRRy wrote:
[snip]
> I just recently added a flag in the database so if the
> email bounces I manully flag the account as a bad
> email so in future emails won't be sent to that users
> email unless they correct their email. This is time
> consuming.
[snip]
D
Hi,
Okay I don't want any code here, well not yet, I am
just wondering if this is possible. And:
- Is it secure/safe ?
- Will it use alot of resources ?
- Will it harm my system or create security holes ?
- Will it do anything bad ? :P
- Should I do it or should I not ? (if it is possible)
Okay
El Vie 12 Dic 2003 00:09, Gerard Samuel escribió:
> What good is this function?
> A quick example of the wall Im running into ->
> $sql = 'INSERT INTO .';
> $result = pg_query($conn_id, $sql);
> if ($result === false)
> {
> var_dump( pg_result_error( $result ) );
I would use here this:
Thanks alot for your help! That was very careless of me..;p I was stil quite a
newbie to php-db coding...
By the way one last favour to ask of u hope u dun mind...
I have a script which was used to INSERT data into the database:
(See script below):
But everytime when I execute it I got the er
you have the GET var in the hyperlink down as just 'id' not 'tutor_id', so change the
hyperlink to
echo "Modify";
or the the get var to $tutor_id = $_GET['id'];
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: 12 December 2003 10:02
To: Griffiths, Daniel
Cc: [
Yes I'm using a hyperlink to access this page (see below)
echo "Modify";
and so I defined my variable "$tutor_id" as $tutor_id = $_GET['tutor_id'];
but i still got the error: "Undefined index: tutor_id
in /usr/local/apache/htdocs/tutor/edit.php "
WHat could be the problem?;(
how are you getting the $tutor_id var?, in your script you are using "$action =
$_GET["action"];" so you will need to define $tutor_id like $tutor_id =
$_GET['tutor_id'], or just use $_GET['tutor_id'].
a form can only put variables in the POST array OR the GET array, and if your using
hyperlink
Hi..
Anyone can help me with this script???I kept getting error saying i did not
define the variable "$tutor_id" and whenever I define it as $tutor_id = $_POST
['tutor_id'], I got error saying there was an "Undefined index"!
What was exactly the problem??
Need help desperately , greatly app
put the schema name before the sequence object you need to increment, i.e.
$sql = "select SCHEMA.TEAM_SEQ.NEXTVAL as \"nextval\" from sys.dual";
Regards,
Neil Morgan
-Original Message-
From: Paul Miller [mailto:[EMAIL PROTECTED]
Sent: 12 December 2003 00:05
To: [EMAIL PROTECTED]
Subject
yes, and that's why i'm appealing for help on how to stripslashes when it
comes to the Shift_JIS character set...
will really appreciate advises! thanx lots!
- Original Message -
> OK, if you *know* that the data has been through addslashes() (or
equivalent
> eg magic_quotes_gpc) then do
On Friday 12 December 2003 14:47, Ng Hwee Hwee wrote:
> i'm doing a form (form.php)
> 1) user comes to form.php
> 2) user enters details and press submit
> 3) details get passed to form action verify.php
> 4) verify.php puts all the $_POST into an array $formVars
> 5) verify.php session_register("
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