Did not see any attachment...? The upgrade might have been the
problem. You might need to recompile or reinstall php...
Christian Schlaefcke wrote:
This looks like it is enabled. I recently upgraded mysql to version
4.1.4. Maybe this causes the problem. Do I have to reinstall PHP it is
still th
pls. help.
i have grant all to one of my tables made in mysql. now when i want to
retrieve the data through PHP, following error is coming
=
select command denied to user: '[EMAIL PROTECTED]' for table
'timeframe'
=
pls. advise what went wrong.
with best wishes
balwant
--
PHP D
If the threadID column is an int, you don't need to wrap the $threadID
variable in quotes.
HTH ~randy
On Tue, 14 Sep 2004 00:05:56 +0200, -{ Rene Brehmer }-
<[EMAIL PROTECTED]> wrote:
> hi gang
>
> I'm working on optimizing the SQL for my forum system, but have run into a
> problem trying to opt
hi gang
I'm working on optimizing the SQL for my forum system, but have run into a
problem trying to optimize the function for deleting a thread with
accompanying stats data and posts from the database using 1 query.
The current function, that works, looks like this:
// delete all traces of a th
Thanks to help here I was able to overcome some ivalid
query errors.
Now I'm back, (probably the same mistake)
It's coming off of this line:
$sql .= " And
PostStart >= DATE_SUB(CurDate(), Interval
['search_fd1'] day )";
The 'search_fd1' is one of the form fields where a
list of val
This looks like it is enabled. I recently upgraded mysql to version
4.1.4. Maybe this causes the problem. Do I have to reinstall PHP it is
still the version I got with the installation of my distro (Fedora Core
2).
I attached what phpinfo produced...
Am Mo, den 13.09.2004 um 17:20 Uhr +0300 schri
Look at the phpinfo() page and see whether you find a section with
information on MySQL. If it isnt there, it is likely to do with the way
you compiled AMP.
Christian Schlaefcke wrote:
Am Mo, den 13.09.2004 um 9:27 Uhr -0400 schrieb John Holmes:
From: "Christian Schlaefcke" <[EMAIL PROTECTE
Blackwater,
On Sep 10, 2004, at 12:39 PM, blackwater dev wrote:
Hello,
I need to grab the max value of all of the data in a table grabbing
the max total for each client. Example.
T1
idtotal clientid
1 100 111
2 200 111
3 100 112
Aaron,
I agree with what Mark said. But I just want to say what I noticed off
hand...
On Sep 10, 2004, at 11:13 AM, Aaron Todd wrote:
I'm trying to run an INSERT query on my mysql database and it isnt
working.
Here is the query:
$updatequery = "UPDATE `users`
SET
('c
Am Mo, den 13.09.2004 um 9:27 Uhr -0400 schrieb John Holmes:
> From: "Christian Schlaefcke" <[EMAIL PROTECTED]>
>
> > This is what I have in my php.ini
> >
> > error_reporting = E_ALL
> > display_errors = On
>
> Have you looked at a phpinfo() page to ensure you're editing the correct
> php.i
From: "Christian Schlaefcke" <[EMAIL PROTECTED]>
This is what I have in my php.ini
error_reporting = E_ALL
display_errors = On
Have you looked at a phpinfo() page to ensure you're editing the correct
php.ini?
In the first block, it tells you what php.ini file PHP is using. If it just
lists a
This is what I have in my php.ini
error_reporting = E_ALL
display_errors = On
display_startup_errors = On
log_errors = On
log_errors_max_len = 1024
ignore_repeated_errors = Off
ignore_repeated_source = Off
report_memleaks = On
track_errors = On
html_errors = On
Tried both:
error_log = /var/log/
If you have access to your php.ini file, take a look for the Error
Reporting settings. It may be set to none, to to log the errors to
syslogd or a file.
Mark
On Mon, 13 Sep 2004 12:48:33 +0200, Christian Schlaefcke
<[EMAIL PROTECTED]> wrote:
> Hi Folks,
>
> I have a problem getting a php script
Hi Folks,
I have a problem getting a php script running. It seems that the script
just dies when calling the function mysql_connect("host", "username",
"passwd"). I put two debugging echoes (one in front and one afterwards)
in the script but only the first one appears.
There are no errormessages.
My suggestion is:
select u.username, g.group_name from usertable u inner join grouptable g on u.id=g.user_id;
ENJOY !!
Arné Klopper
System Developer
NetCB Solution(Pty) Ltd.
www.netcb.com
**
Looking for clarification...Say that I have a user table and
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