Simply put, you create a couple of css classes that make the row look the
way you want and then
while ($rows = mysql_fetch_array($result))
{
$color = ($counter % 2 ==0) ? "rowclass1" : "rowclass2" ;
echo "...";
}
Its essentially the same thing, just neater and lets you concentrate on the
cod
Bastien Koert <[EMAIL PROTECTED]> wrote:
>
> $row1 = "FF";
> $row2 = "AA";
> $counter = 0;
>
> while ($rows = mysql_fetch_array($result))
> {
> $color = ($counter % 2 ==0) ? $row1 : $row2 ;
>
> echo "...";
>
> }
>
>
> bastien
>
>
> ps: a class css definition would be better here
Sorry, that's shorthand.. is the same as:
is the end tag..
On Monday 14 November 2005 6:26 pm, Jeff Grossman wrote:
> Micah Stevens <[EMAIL PROTECTED]> wrote:
> > You don't have to output two rows.. just do this:
> >
> > $color = "red"; // init first color.
> > while ($row = mysql_fetch_ass
Micah Stevens <[EMAIL PROTECTED]> wrote:
>
> You don't have to output two rows.. just do this:
>
> $color = "red"; // init first color.
> while ($row = mysql_fetch_assoc($data)) {
>if ($color == "red") {
>$color = "blue";
>} else {
>$color = "red";
Sorry if I sounded offended, I'm not. I was just curious because the advantage
wasn't obvious to me. I see your point now though. Thanks for the insight.
On Monday 14 November 2005 6:12 pm, Ajree wrote:
> Micah Stevens wrote:
> > I don't see what's more elegant about. They have a good point tha
Micah Stevens wrote:
I don't see what's more elegant about. They have a good point that you only
need to do one out of the two, but doing it in Javascript versus PHP only has
the advantage that it puts the processing load for that on the client
computer.
Am I missing something?
The second
I don't see what's more elegant about. They have a good point that you only
need to do one out of the two, but doing it in Javascript versus PHP only has
the advantage that it puts the processing load for that on the client
computer.
Am I missing something?
On Monday 14 November 2005 5:25 p
Take a look at this article on ALA:
http://www.alistapart.com/articles/zebratables/
It makes markup more elegant than repeated .
--
Ajree
Jeff Grossman wrote:
I have a table, where each line is the output of a query from a MySQL
database. I do not use borders, so the page is a little difficul
...";
}
bastien
ps: a class css definition would be better here
From: Jeff Grossman <[EMAIL PROTECTED]>
To: php-db@lists.php.net
Subject: [PHP-DB] Table Output Question
Date: Mon, 14 Nov 2005 15:37:36 -0800
I have a table, where each line is the output of a query from a MySQL
database.
You don't have to output two rows.. just do this:
$color = "red"; // init first color.
while ($row = mysql_fetch_assoc($data)) {
if ($color == "red") {
$color = "blue";
} else {
$color = "red";
}
?>
..
I ha
I have a table, where each line is the output of a query from a MySQL
database. I do not use borders, so the page is a little difficult to
read sometimes. Is it possible, or how do I, alternate the background
color of each row when I output it?
My code is like this:
while (query) {
At 04:40 PM 11/14/2005, Chris Payne wrote:
Hi there everyon,
I have a set of form fields dynamically generated but each item must contain
2 pieces of data - the input from the field AND the id that the input
represents from the DB. I had this info a while back but had a major HD
crash and lost
You could just seperate the data in the field's value with a delimeter like |
or something you wouldn't see in the data, then explode() based on that?
What kind of field are you using? Your explanation is very vague.
On Monday 14 November 2005 12:40 pm, Chris Payne wrote:
> Hi there everyon,
Hi there everyon,
I have a set of form fields dynamically generated but each item must contain
2 pieces of data - the input from the field AND the id that the input
represents from the DB. I had this info a while back but had a major HD
crash and lost the info I had, how can I do this easily i
Hello,
1. Upgrade to the latest version (1.3.0rc3 beta), AFAIK 1.2.3 doesn't
support custom containers if you use this feature
2. allow_call_time_pass_reference must be 'on', otherwise it fails (produces
an error message)
3. turn error_reporting(E_ALL); and see if there are any notices/warnings
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