Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread ioannes
I was unsure what was meant by FILE in php - is that the global? How do I reference a remote site's jpg file into FILE? Then how to I create the output from the php into stdout - using the return of a function? or print? Then how to launch rsynch - I understand how to call it from cron,

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread ioannes
OK but I could execute the script on the target server, which is also mine. So the jpg on the source is actually the remote server, I would be reading a remote file and writing it to the server which is executing the script. Chris wrote: ioannes wrote: This is too advanced for me and

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread ioannes
I am and have been reading http://samba.org/ftp/rsync/rsync.html, which is one web page but 44 real pages. I see that FILE is a term used the rsynch script. Is this something output from the php script, and if so how is it channelled from one to the other? I see the following: - start

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread Daniel Brown
On Feb 5, 2008 9:49 AM, ioannes [EMAIL PROTECTED] wrote: OK but I could execute the script on the target server, which is also mine. So the jpg on the source is actually the remote server, I would be reading a remote file and writing it to the server which is executing the script. Then

RE: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread Mr Webber
The pattern in you --include-from=FILE_CONTAINING_FILENAME_PATTERNS could be just a list of files that you can generate from your PhpScript. Get it now? -Original Message- From: ioannes [mailto:[EMAIL PROTECTED] Sent: Tuesday, February 05, 2008 1:22 PM To: php-db@lists.php.net Subject:

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread ioannes
OK, so how would I hand over the list of files from php to the script? And am I right that I would write the rsynch code in a text file called anything.txt and the rsync at the start of the line is what calls up the rsynch program, unlike php where you need to call it something.php -

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread ioannes
Am I right in thinking that exec() executes a string as a call to a program which executes in a shell? So am I to write: $callthis=the contents of my rsynch file; exec($callthis); ? John ioannes wrote: OK, so how would I hand over the list of files from php to the script? And am I right

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2008-02-05 Thread arafat uddin
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Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread Daniel Brown
On Feb 5, 2008 2:57 PM, ioannes [EMAIL PROTECTED] wrote: Am I right in thinking that exec() executes a string as a call to a program which executes in a shell? So am I to write: $callthis=the contents of my rsynch file; exec($callthis); Filtered :-\ -- /Dan Daniel P. Brown Senior

Re: [PHP-DB] Copying an image from one server to another

2008-02-05 Thread Chris
ioannes wrote: OK but I could execute the script on the target server, which is also mine. So the jpg on the source is actually the remote server, I would be reading a remote file and writing it to the server which is executing the script. OK I guess i completely misunderstood what you were