this on my machine (MySQL ver: 3.23.54) and on the customer's
server
(ver: 4.0.14), and got the same results. Obviously I'm not getting the
logical scheme right. If anyone can point out the problem or suggest a
better way to write the query I'd appreciate it.
Thank you, Boaz Amit
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I say we nuke it from orbit. That's the only way to be sure. Besides who gives a damn
anyway.
ff
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= explode('|', $crispy);
$session_id = $cookie_data[0];
$charnick = $cookie_data[1];
---
Regards,
Boaz Amit
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more experienced and advanced than my own.
---
regards,
Boaz Amit
Hello Pranot,
On 16-Jul-01 06:09:33, you wrote:
hi.. friends
i have a database (mysql) in which their r many records. Through PHP i
want
them to display on the page.
Main requirement
