Another resource for source code, when will Google stop being so
innovative... :)
http://www.google.com/codesearch
Jeremy
Jeremy Peterson, MACS
Automation Systems Administrator
Education Technology Services
Moody Bible Institute
820 N. LaSalle Drive
Chicago, IL, 60610
Email
AIL PROTECTED]&*+=-]+\.php$/
Keep 'em coming!
--
Eric Pement - [EMAIL PROTECTED]
Educational Technical Services, MBI
Jeremy Peterson, MACS
Automation Systems Administrator
Crowell Library
Moody Bible Institute
820 N. LaSalle Drive
Chicago, IL, 60610
Email: [EMAIL PROTECTED]
Phone: 312.329.8081
Fax:312.329.8959
I am having a problem with a query that has a pound sign in it. The
results are quite puzzling, it seems like the page doesn't load if the
query is present. I have tested this on other tables without the pound
sign and they work beautifully, seems like the pound sign is the
troublemaker to me
Yep, I wish I could name the fields, but alas it is not my database
application. For some reason it works... :)
When I use isql it works as expected, thus the problem.
At 10:41 PM 8/5/2003 -0400, John W. Holmes wrote:
Jeremy Peterson wrote:
I am having a problem with a query that has a pound
e, you can reference
that information to determine how to proceed.
Here's the doc: http://www.php.net/manual/en/ref.session.php
--Dave
On Thu, 2003-01-09 at 11:29, Jeremy Peterson wrote:
> David,
>
> I have ldap working, my problem is the second half of my question.
>
> Th
))to
verify a username/password on the LDAP server. Here's some PHP code that
will do it or you:
$ldap_server = "example.com"; // change to your LDAP server host name
$ldap_port = 389; // might be different for your server
$pw = "yourpassword"; // change to your password
$
I am working on a script that will authenticate on a central system my
company has devised for us to use (LDAP) and then authenticate them to
other sites that I want them to access (Online Databases and other
electronic resources I do not control but pay lots of money for all
students to access).
Sure-
$test = "text1";
if(substr($test, -1) == 1){
print "do something";
}
else{
print "didn't equal 1 ";
At 08:00 AM 5/17/2002 -0400, Natividad Castro wrote:
>Hi to all,
>how can I evaluate a variable?
>For example
>$test = "test1";
>then I want to evaluate if $test contains
select * from table where id in (1,3,5,10,'etc')
At 08:22 PM 2/7/2002 +0100, Raymond Lilleodegard wrote:
>Hi!
>
>Is there a way to get the rows with id's like 1, 3, 5, and so on or 2, 4, 6,
>...?
>
>
>Best regards Raymond
>
>
>
>--
>PHP Database Mailing List (http://www.php.net/)
>To unsu
Hello,
I am not sure why you want to do this. Wouldn't it be better to use
calculate the days from the date signed up, rather than through updating
your database every day. Try using datediff.
Jeremy
At 01:51 PM 2/4/2002 -0800, Jennifer Downey wrote:
>Hi,
>
>I am having problems with this c
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