Do you have postgres module for PHP installed? This will probably be the
cause.
Didier Gasser-Morlay napsal(a):
Hello,
I tried all day yesterday to setup a brand new machine with a fresh
Linux install; with apache 2.2.10 (from source) php 5.2.9 (from
source) and PostgresQL 8.3.7 (from the ve
Look what extensions are you loading. You should find that in php.ini
file. Maybe something nasty happened and you php.ini has
extension=php_oracle.dll instead of extension=php_oracle.so. Also, if
you are about to compile a module for PHP, first you have to run phpize,
than ./configure and make
Look at www.phpclasses.org ;)
Wilson Osemeilu napsal(a):
I need a simple php mysql image upload script with display script too and to
make this easier the mysql database table to use
--
S pozdravem
Daniel Tlach
Freelance webdeveloper
Email: m...@danaketh.com
ICQ: 160914875
M
Then you should put some debugging around the connection code.
|$pgconn = pg_connect("host=localhost port=5432 dbname=test user=test
password=test")| or die("Problem with connection to PostgreSQL:
".pg_last_error());
So you can be sure that you are really connected. Also you can use
pg_resul
Can you provide us with some of the queries you send to database? I'd
suggest you test it with some easy and simple one, like this on from PHP
documentation:
|$result = pg_query_params($dbconn, 'SELECT * FROM shops WHERE name = $1',
array("Joe's Widgets"));
|
Brandon Metcalf napsal(a):
I'm f
I'd suggest using Google, but you can try phpclasses.org instead. There
you'll find everything you need.
Wilson Osemeilu napsal(a):
I need multi user login php script which each user can upload their profile
picture..
i mean
the index.php
register.php
login.php
changepassword.php
etc
Hello,
you're not fetching the query results.
$query = "SELECT currval('\"tblPeople_peopleId_seq\"')";
$result = pg_query($query) or die("Can't execute 4th query");
if ($result != false) {
$row = pg_fetch_row($result);
echo "person id is " . $row[0] . "";
}
Hi Vee,
You have it all in that error :) You're calling function on
non-object. Look into the basket.php. On the lines where you call the
MySQL query you have $con->query($sql) but there is no decalaration of
$con object anywhere before.
I think you have an MySQL layer included (mysql.
--+---+++
404 | Ilka| | Ott| t | t
410 | Elinor | | Ostrom | t | t
374 | Gregory | | O'Hare | t | t
33 | Terry | J.| Ord| t | t
(4 rows)
On May 10, 2009, at 4:41 AM, danaketh wrote:
I&
I'd suggest you to copy the echoed queries and run them directly in
terminal (if you have access). Also if you have remote access to the
database and can use tools like pgAdmin or Navicat, that could help you
with testing. Or send me the table structure and I'll try them myself ;)
Carol Walter
Hi,
you should post the INSERT query too. I'd recommend you to print the
query before running it. Just put echo $query; before/after pg_query().
You'll see what are you sending to the database. This may help you find
the problem. Also using ` instead of " in query may help you to make it
e
Can't say for sure where the problem is but seems to me that you're
using global variables instead of $_GET and $_POST. After sending the
form, you should access it's content using $_POST...
if (isset($_POST['get_name'])){
echo "People Id = ".$_POST['GetName']."";
}
This should solve th
Don't see session_start() in your script. If you work with SESSION, you
must have it on the first lines of the file (before any output and work
with $_SESSION so it's good to put it on the first lines).
And it must be in every file which works with them (except for included
files). It should l
Try that query in console or use Navicat/phpMyAdmin to run it. Remove
the HAVING part to see if the SELECT returns what you need.
Terion Miller napsal(a):
Thanks Martin, oddly enough that still doesn't pull any results, it won't
even print the variables if I try to list them to see, I know my d
Maybe LEFT instead of INNER?
Terion Miller napsal(a):
Hi Everyone! I am having problems getting an INNER JOIN to work and need
some tips trouble shooting where the problem may be.
What I'm trying to do is match up AdminID's from two tables and display only
that users orders, sounds simple enoug
This is solved by using FOREIGN KEY but I'm not sure if MySQL have them
present or just planned for some future release.
mrfroasty napsal(a):
I am quite new to database designs, I have a problem in my design...I
can actually feel it, but I am not quite sure if there is a feature in
mysql or I h
Well, if you're using some good database layer, you can have for example
insert.php file with query template and give it some parameters.
$arr = array(
'field1' => 'value1',
'field2' => 'valuer2',
...
);
$query = layer::query('INSERT INTO [table]', $arr);
Then you will need just to pr
Well, seems to me like a problem with quotes you're using in query...
The ` quotes you're using doesn't work, when I tried to use them in PHP
called query. Maybe you should try use single quotes and if they works.
boclair napsal(a):
I need help to track down the cause of the error,"Could not r
Hi,
the first choice is probably the best for you. When you think about
second solution, it will be a nightmare when you have 1000+ databases
and have to administrate them from one central system (if you're about
to do it like this). The third solution looks little complicated to me -
have
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