> Asunto: Re: [PHP-DB] Arraying JOINED tables
>
> Try find out if you have an error in your query, like this:
>
> $query = "SELECT * FROM logins,auth WHERE logins.authname = $variable1
> AND auth.authid = $variable2";
> if ( $result = @mysql_query($query) ) {
>
ther thing... maybe you have fields in both table logins and auth
with the same name
Denis Arh
- Original Message -
From: "César Aracena" <[EMAIL PROTECTED]>
To: "PHP DB List" <[EMAIL PROTECTED]>
Sent: Sunday, June 16, 2002 8:59 AM
Subject: [PHP-DB] Arrayi
Hi all.
This should be an easy one for all of you. I want to make a basic SELECT
query from two tables and fetch all the results into one array. Im
doing it like this:
$query = "SELECT * FROM logins,auth WHERE logins.authname = $variable1
AND auth.authid = $variable2";
$result = mysql_query($qu
Hi all and sorry if this message is sent many times, but Im having
problems switching mailing lists from one email address to another.
This should be an easy one for all of you. I want to make a basic SELECT
query from two tables and fetch all the results into one array. Im
doing it like this:
Hi all.
This should be an easy one for all of you. I want to make a basic SELECT
query from two tables and fetch all the results into one array. Im
doing it like this:
$query = "SELECT * FROM logins,auth WHERE logins.authname = $variable1
AND auth.authid = $variable2";
$result = mysql_query($qu
Hi all. Hope youre all alright since I dont see any of you writing for
some time now ;-)
This should be an easy one for all of you. I want to make a basic SELECT
query from two tables and fetch all the results into one array. Im
doing it like this:
$query = "SELECT * FROM logins,auth WHERE lo
