Dear List -
I am trying to use prepared statements with the following code:
$allowed_fields = array
('Cust_Num' = 'i', 'Fname' = 's', 'Lname' =
's', 'Street' = 's','City'= 's', 'State' = 's', 'Zip' = 'i',
'Phone' = 'i', 'Notes' =
$stmt = mysqli_stmt_prepare( $cxn, $sql12 );// line 507
//Warning: mysqli_stmt_prepare() expects parameter 1 to be mysqli_stmt, object
given in /var/www/x5.php on line 507
$cxn is not a mysqli_stmt. Are you perhaps passing the mysqli database
resource instead of the statement?
See
Dear list -
Thanks to all for your help.
I hope [??] that this question will solve all the remaining problems.
So that we are on the same page, here is what was previously stated.
mysqli_stmt_bind_param expects three variables, in this order
mysqli_stmt_bind_param($stmt, num, $a, $b,
Dear list -
SEE CORRECTION IN $_POST VARIABLE BELOW.
Thanks to all for your help.
I hope [??] that this question will solve all the remaining problems.
So that we are on the same page, here is what was previously stated.
mysqli_stmt_bind_param expects three variables, in this order
Ethan,
Please accept my apologies for the minor errors in the untested code I
previously provided for your edification.
Consider the following tested code:
?php
/*
CREATE TABLE test (id INT UNSIGNED PRIMARY KEY AUTO_INCREMENT, data
INT UNSIGNED);
INSERT INTO test (data) VALUES
Ethan,
I believe the root of your problem is that you are passing $bind3 as a
string to mysqli_stmt_bind_param() where the function was expecting
multiple arguments.
Let's say $binder = array( 'one', 'two', 'three' ); // I'll call this
$arguments in my example below
and $typer = array(
Dear List -
Thanks to all for your responses.
Here is another one
I wish to accomplish the following
mysqli_stmt_bind_param($stmt, 'sis', $_POST['Site'], $_POST['MedRec'],
$_POST['Sex']);
This statemnt was hand coded. I wish to be able to generalize it.
Therefore -
$sql11 =
Dear List -
Here is another problem I am having with prepared statements. The last
one was INSERT, this one is SELECT.
Here is the database:
mysql describe Intake3;
++-+--+-+-+---+
| Field | Type| Null | Key | Default | Extra |
Does the list of the SELECT fields not have to match the variables you are
binding? E.g. if you do not include MedRec in your SELECT then you have no
MedRec data to bind from your $sql11 variable to the $MedRec varable and
then nothing to print there... or what? Am I just fabulating? :).
Cheers,
Dear List -
-- THANKS TO ALL. See below --
Here is another problem I am having with prepared statements. The last
one was INSERT, this one is SELECT.
Here is the database:
mysql describe Intake3;
++-+--+-+-+---+
| Field | Type| Null | Key |
On Sun, Sep 2, 2012 at 6:45 AM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I wish to accomplish the following with prepared statements:
$stmt = mysqli_stmt_init($cxn);
if($stmt = mysqli_stmt_prepare($stmt, INSERT INTO Intake3 (Site,
MedRec, Fname, Lname,
Ethan Rosenberg, PhD
/Pres/CEO/
*Hygeia Biomedical Research, Inc*
2 Cameo Ridge Road
Monsey, NY 10952
T: 845 352-3908
F: 845 352-7566
erosenb...@hygeiabiomedical.com
On 09/02/2012 08:33 AM, Matijn Woudt wrote:
On Sun, Sep 2, 2012 at 6:45 AM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com
On Sun, Sep 2, 2012 at 6:45 AM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I wish to accomplish the following with prepared statements:
$stmt = mysqli_stmt_init($cxn);
if($stmt = mysqli_stmt_prepare($stmt, INSERT INTO Intake3 (Site,
MedRec, Fname, Lname,
On Sun, Sep 2, 2012 at 10:41 PM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
On Sun, Sep 2, 2012 at 6:45 AM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I wish to accomplish the following with prepared statements:
$stmt =
Dear List -
I wish to accomplish the following with prepared statements:
FYI -
The Database:
mysql describe Intake3;
++-+--+-+-+---+
| Field | Type| Null | Key | Default | Extra |
++-+--+-+-+---+
| Site
Hi all,
I am struggerling with a prepared statement (may not even be suited)
$stmt = $db-stmt_init();
if($stmt-prepare(SELECT title,live,where FROM content))
{
$stmt-bind_param('sii',$t,$l,$w);
## This bit here
$stmt-execute();
$stmt-bind_result($title,
On Fri, Nov 11, 2011 at 10:41 AM, Ron Piggott
ron.pigg...@actsministries.org wrote:
?php
$dsh = 'mysql:host=localhost;dbname='.$database;
$dbh = new PDO($dsh, $username, $password);
#query for the authorization code
$query = SELECT `authorization_code` FROM
I have two questions about Prepared Statements from the code below:
#1:
The purpose of the first $query is to determine if the authorization code
supplied is both accurate and also live
- When the authorization code is generated it is given a time frame when it
must be used in. The columns
On Fri, Nov 11, 2011 at 5:41 PM, Ron Piggott
ron.pigg...@actsministries.org wrote:
I have two questions about Prepared Statements from the code below:
#1:
The purpose of the first $query is to determine if the authorization code
supplied is both accurate and also live
- When the
I need my Prepared Statement database connection to be able to connect with two
different databases (which use the same username / password).
They are assigned variables
$database1 and $database2
What I have been using so far is:
$dsh = 'mysql:host=localhost;dbname='. $database1;
$dbh =
On 2011-09-30, at 8:26 PM, Ron Piggott ron.pigg...@actsministries.org wrote:
I need my Prepared Statement database connection to be able to connect with
two different databases (which use the same username / password).
They are assigned variables
$database1 and $database2
What I
What command will tell me the # of rows the SELECT query retrieved using
Prepared Statements.
$dsh = 'mysql:host=localhost;dbname='.$database;
$dbh = new PDO($dsh, $username, $password);
$stmt = $dbh-prepare($query);
$stmt-bindParam(':email', $email);
$stmt-bindParam(':pass', $pass);
$stmt-rows() should give you the number of rows returned.
Giff
On Mon, 2011-05-23 at 18:53 -0400, Ron Piggott wrote:
What command will tell me the # of rows the SELECT query retrieved using
Prepared Statements.
$dsh = 'mysql:host=localhost;dbname='.$database;
$dbh = new PDO($dsh,
Hey friend!
You can use the PDOStatement::RowCount, but there is a problem
(extracted from the PHP Manual,
http://php.net/manual/en/pdostatement.rowcount.php):
PDOStatement-rowCount - Returns the number of rows affected by the
last SQL statement. If the last SQL statement executed by the
I am just starting to use Prepared Statements and am in a learning curve.
I am working on the code below. It is for a directory. This is to select the
listing for updating.
How do I tell if there are more than 1 search result?
Am I correctly retrieving the results, if there is more than
I am trying to implement Prepared Statements on my web site and this is the
first time I have ever used this.
#1) I received the error “class mysql not defined”. That is a reference to the
first line of code (below) where the database connection is established.
#2) How do I assign the
Is it possible?
Just checking...
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When I use pconnect to connect to a db2 back end, I get the expected faster
connection times. However, when the site is under any sort of load (6 or
more concurrent accesses), we have noted that the time spent preparing
statements increases greatly (execution time remains fairly consistent
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