Dear list -
This did not seem to post, so I am sending it again.
If it did post, and I missed it, my apologies.
Ethan
Dear list -
I have the following code:
$query = "select * from Intake3 where 1";
$allowed_fields = array('Site', 'MedRec', 'Fname', 'Lname',
Dear Ethan
It seems you are trying to build a query.But you are not getting field
names. If you required field names then change the following line to
foreach ( $allowed_fields AS $field => $_POST['field'])
to
foreach ( $allowed_fields AS $field)
This would convert the variable field to value. I
At 12:13 AM 2/10/2012, Amit Tandon wrote:
Dear Ethan
It seems you are trying to build a query.But you are not getting field
names. If you required field names then change the following line to
foreach ( $allowed_fields AS $field => $_POST['field'])
to
foreach ( $allowed_fields AS $field)
This
Dear Ethan
The line you are getting is because the $_POST[fieldname] is blank. So for
the following line
if ( ! empty( $_POST['field'] ) )
change it to
if ( ! empty( $_POST["$field"] ) )
Your line : Program is searxchinbg for variable name field
New line : The Program is seacging for varable st
At 12:48 AM 2/10/2012, Amit Tandon wrote:
Dear Ethan
The line you are getting is because the
$_POST[fieldname] is blank. So for the following line
 if ( ! empty( $_POST['field'] ) )
change it to
 if ( ! empty( $_POST["$field"] ) )
Your line : Program is searxchinbg for variable name field
N
At 12:48 AM 2/10/2012, Amit Tandon wrote:
Dear Ethan
The line you are getting is because the
$_POST[fieldname] is blank. So for the following line
 if ( ! empty( $_POST['field'] ) )
change it to
 if ( ! empty( $_POST["$field"] ) )
Your line : Program is searxchinbg for variable name field
N
