Re: [PHP-DB] REVISED; need INSERT help

2003-02-01 Thread Edwin Boersma
What about using a form identifier? In each form, use input type=hidden name=formident value=form1 and so on. Then, use: switch ($formident) { case form1: your action for this form break; case form2: and so on. Edwin Mark wrote: I haven't been following any other

[PHP-DB] REVISED; need INSERT help

2003-01-27 Thread Addison Ellis
hello again and i am sorry i was not more specififc in my last post. here is where i am confused: else { $today = date(Y-m-d h:m:s); $sql = INSERT INTO ads ()