$sql=insert into $table set Name = '.$_POST[elementName].';
or even better:
$sql=insert into .$table. set Name = '.$_POST[elementName].';
But the method both Jake and Bao suggested will also work (temporary var)...
--
// DvDmanDT
MSN: [EMAIL PROTECTED]
Mail: [EMAIL PROTECTED]
Adam Reiswig [EMAIL
$sql=insert into $table set Name = '$_POST[elementName]';
The problem with this is that you need to use curly braces around the
variable being substituted in the string. Also use single quotes around the
array index.
$sql=insert into $table set Name = '{$_POST['elementName']}';
See the
