Hello.
I am using this:
$sql = "SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE
'%$_GET[word]%'";
But I want exactlu ID, not one part of many possibles Ids in the DB.
How can I do that?
Thanks
+ _
// Emil
Emiliano Boragina wrote:
> Hello.
>
> I am using this:
> $sql = "SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE
> '%$_GET[word]%'";
>
This doesnt work?
$sql = "SELECT * FROM table WHERE ID='some_id' AND title='some_title';
--
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OSS:Gentoo Linux
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Hardw
$sql = "SELECT * FROM table WHERE ID ='$_GET[id]' AND title LIKE
'%$_GET[word]%'";
Original Message ----
Subject: [PHP-DB] SELECT LIKE with "%'" and without "%'"
From: Emiliano Boragina
To: php-db@lists.php.net
Date:
On May 2, 2009, at 6:43 PM, Emiliano Boragina wrote:
Hello.
I am using this:
$sql = "SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE
'%$_GET[word]%'";
But I want exactlu ID, not one part of many possibles Ids in the DB.
How can I do that?
PLEASE tell me your cleaning that inpu
"Eleonora De Marinis" , haber iletisinde sunlari
yazdi:49fe92d0.2060...@garr.it...
> $sql = "SELECT * FROM table WHERE ID ='$_GET[id]' AND title LIKE
> '%$_GET[word]%'";
>
>
>
> ---- Original Message
> Subject: [PH
