Thanks, but DISTINCT doesn't work... But I managed to get it to work
anyway by including
namn_1 NOT LIKE 'H%'
in the second WHERE-clause...
Micah Stevens wrote:
use DISTINCT?
On Sunday 30 January 2005 12:51 pm, Bobo Wieland wrote:
Anyone that can help me with this one? I want this
Anyone that can help me with this one? I want this SQL-statement to
retrive only distinct values from the original table column named (not
the AS stuff)
(
SELECT * , namn_2 AS sec_namn, namn_1 AS one
FROM sortiment
WHERE namn_1 LIKE 'H%'
)
UNION (
SELECT * , UPPER( namn_2 ) AS sec_namn, namn_2
use DISTINCT?
On Sunday 30 January 2005 12:51 pm, Bobo Wieland wrote:
Anyone that can help me with this one? I want this SQL-statement to
retrive only distinct values from the original table column named (not
the AS stuff)
(
SELECT * , namn_2 AS sec_namn, namn_1 AS one
FROM sortiment
-mail)
Subject: Re: [PHP-DB] SQL prob (DATE_FORMAT)
Russ,
I'm a bit of a novice, but I would have thought that the DATE_FORMAT
function would only work if the field had been defined as a DATE field
type.
If you are storing the date as an integer eg: 20020705 (today), why not
format your current
