Can anyone help me figure out what is wrong with this syntax. Thanks.
list($qh,$num) = dbQuery(SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 .
FROM $USER_TABLE WHERE username='$username');
$data = dbResult($qh);
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Hi
is the syntax error reported for the php or the SQL? Better yet,
supply the actual error message, so we can see for ourselves
Niel
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JD wrote:
Can anyone help me figure out what is wrong with this syntax. Thanks.
list($qh,$num) = dbQuery(SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 .
FROM $USER_TABLE WHERE username='$username');
$data = dbResult($qh);
No need to repost your
JD wrote:
Can anyone help me figure out what is wrong with this syntax. Thanks.
list($qh,$num) = dbQuery(SELECT password AS passwd1,
$DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 .
FROM $USER_TABLE WHERE username='$username');
$data = dbResult($qh);
No need to repost your
Hi
is the syntax error reported for the php or the SQL? Better yet,
supply the actual error message, so we can see for ourselves
Niel
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PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
it's always eaiser to count the parens and braces backwards
to make sure
they're all there. i do it all the time.
... or you use a cool Editor (like UE32) which will do this
job for you =8)
Greetinx,
Mike
(Germany)
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Hi
Anyone have any idea of what the syntax error in this statement is?
else if (($op == ds) ($action == sub) ($password == $passnog)
($password)
(!eregi(^([a-z0-9_]|\\-|\\.)+@(([a-z0-9_]|\\-)+\\.)+[a-z]{2,4}$,$email))
{
It worked fine until I added the tricky part:
Marc S. Bragg [mailto:[EMAIL PROTECTED]] wrote:
Hi
Anyone have any idea of what the syntax error in this statement is?
else if (($op == ds) ($action == sub) ($password ==
$passnog)
($password)
(!eregi(^([a-z0-9_]|\\-|\\.)+@(([a-z0-9_]|\\-)+\\.)+[a-z]{2,4
}$,$email))
{
It
