Re: [PHP-DB] Warning: Unable to jump to row...

2003-03-31 Thread Ronan Chilvers
Hi Ben Comments inline On 31 Mar,2003 at 13:46 Benjamin Trépanier wrote: > border="0"> > > > $i!=$id_news_ > $id= mysql_result($req,$i,"id"); > $titre = mysql_result($req,$i,"titre"); > $date = mysql_result($req,$i,"date"); > $heure = mysql_result($req,$i,"heu

[PHP-DB] Warning: Unable to jump to row...

2003-03-31 Thread Benjamin Trépanier
Hi, I'm trying to using a news script and improve somes with a query. $req = MYSQL_QUERY("SELECT * FROM $TBL_NEWS"); $res = MYSQL_NUM_ROWS($req); ?> I want that my script show the content of the rows corresponding to my Variable called: Id_News_ So the variable is moving w