1 failed");
> sybase_free_result($result);
>
> $result=sybase_query("insert into pub_info
> values(0001,null,'test')") or
> die("query2 failed");
> sybase_free_result($result);
>
> $result=sybase_query("select * from pub_info");
&g
Hi,
I would suggest removing @ in front of the sybase_query. This way your code will
produce warnings and messages from the server. That could help you debugging. You
could also try to execute the query in Query Analyzer on the SQL Server.
- Frank
> Please take a look into my simple php code.
Please take a look into my simple php code. Why does
this program die on "query2 failed" but a new record
acturally is inserted into table "pub_info"?
I asked this question last week, but didn't get any
answer so far. If you don't see any problem in there,
please let me know. This is my last try
