Re: [PHP-DB] easy date format question

2002-03-04 Thread Dan Brunner
Hello!! it should be $today = Date("Y"-"m"-"d"); Dan On Friday, March 1, 2002, at 04:50 PM, [EMAIL PROTECTED] wrote: > should be simple as pie, of course, but i can't find a straightforward > syntax example in the documentation. i'm trying to change the PHP date > format to mysql's. > > my

RE: [PHP-DB] easy date format question

2002-03-02 Thread Boaz Yahav
or : $sql="INSERT INTO table (date) VALUES (now())"; -Original Message- From: Jim Lucas [php] [mailto:[EMAIL PROTECTED]] Sent: Saturday, March 02, 2002 2:11 AM To: [EMAIL PROTECTED]; Matthew Crouch Subject: Re: [PHP-DB] easy date format question $today = date("Ymd&qu

Re: [PHP-DB] easy date format question

2002-03-01 Thread Jim Lucas [php]
$today = date("Ymd"); $sql = "INSERT into table (date) values ('$today')"; when the $today variable is inserted into a mysql date column it will fit just right. but, if you want to insert it into a timestamp column, you will have to padd it with 6 zero's Jim Lucas www.bend.com - Original Me