Hi
it means that the query did not produce a result - usually this is because
of a problem with the query.
$sql_query = mysql_query("SELECT * FROM cm_customer WHERE emial='$user'");
I am guessing you misspelt email and this should be
$sql_query = mysql_query("SELECT * FROM cm_customer WHERE e
it means mysql_query() filed.
u must check it before using mysql_fetch_row()
f.e.
$query = "bla bla bla";
$result = mysql_query( $query );
if ( $result ){
while ( $row = mysql_fetch_row( $result ) ){
}
}
else {
echo mysql_error( $db_connect );
exit;
}
--
PHP Database Mailing List (http://w
The mysql_num_rows function requires that the argument passed to it
should be a valid MySQL result from a Select statement. Your script
doesn't explicitly establish a connection with the database so you could
be getting an error from that call, hence $sql_query would not be a
valid MySQL result
Hey thanks guys, the email was the problem
I had emial instead of email
Thanks for the assistance.
-Original Message-
From: Peter Lovatt [mailto:[EMAIL PROTECTED]
Sent: Tuesday, January 18, 2005 1:45 AM
To: Earl Clare; php-db@lists.php.net
Subject: RE: [PHP-DB] i am lost (php warning
