My code is much more extense than this, but I guess this is the source of my problem. "arquivo" is a member of a form, it is a file type, declared like <input type="file" name="arquivo">... I need to know if there is a file selected or not, that is the reason of the bug. When I run this code, through the form it does not print anything, even when I choose a file on the previous html (html with a form, with an action calling this script...) My version of PHP is 4.x <?php $nome = $_POST['nome']; $des = $_POST['des']; $eng = $_POST['eng']; $id = $_POST['id']; $tabela = $_POST['tabela']; $tabela_nova = $_POST['dd_tipo']; $arquivo = $_FILES['arquivo']['name']; //Conexao com BD... printf("%s",$arquivo); ?>
Why it is happenig??? _________________________________________ Daniel Castro ICQ#: 12919017 [EMAIL PROTECTED] [EMAIL PROTECTED] _________________________________________ --- O email enviado não tem Vírus Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.365 / Virus Database: 202 - Release Date: 24/5/2002 -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, visit: http://www.php.net/unsub.php