Hi:
Adding a detail to my previous note on the mysql connect problem:
At the point where I attempted to connect, I added a printout of the
error generated when the instruction ran. The two lines now read:
$result = mysql_pconnect("localhost", "api_user", "x97533");
echo "Tried to connect. Pr
Hi:
I have recently upgraded from a Mac G4 running OS 10.3.9 to a
G5 running OS 10.4. I ported a working PHP app and upgraded from PHP
4.3.4 to 4.3.10 and MySQL 4.0.17 to 4.1.11. I am having a problem
connecting to MySQL from PHP.
I can connect to the database using either phpMyADMIN or
Hi:
I have a partially finished app using PHP and MySQL that runs on Mac
G4 running System 10.3.9. Undoubtedly, I upgraded too many things all
at the same time. Something broke. PHP and MySQL are both running. I
can use the latest phpMyADMIN and everything is there in the
database, so that s
Does anyone know of a way to jump from one php script to
another without going through the client browser? The closest I have
been able to come to doing that is to use nested frames where the
parent frame can call multiple php scripts, one for each child frame.
Jim
--
Jim Feldman
14 Linda Lane
Cesar:
I think that the problem is the array in the
"echo" statement. I have found that I have to do
something
like:
$simple = $_COOKIE["MemberId"];
echo "Member ID = $simple";
Hope that helps.
Jim
Hi all,
My head is about to explode here... I am trying to setup a cookie for every
new user
I should first admit to being a php newbie, so the answer may
be obvious, but this looks like a
bug to me. Global variables are OFF. I start a session at the very
top of page "member.php":
session_start();
In a function called from the same page, I store some variables in
the session array:
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