I'm trying to get php 4.3.4 installed as a module for Apache 1.3.28. I
have apache unzipped/untarred and I ran the ./configure script for it
(per the instructions in the PHP install). I then configured php with
the following line-
$ ./configure --with-mysql=/usr/local/mysql \
Brad Pauly wrote:
On Thu, 2004-01-22 at 09:43, Thaddeus J. Quintin wrote:
I'm trying to get php 4.3.4 installed as a module for Apache 1.3.28. I
have apache unzipped/untarred and I ran the ./configure script for it
(per the instructions in the PHP install). I then configured php
I've got a problem with cookies failing.
Here's the setup-
A staging server, RedHat Linux, with php 4.3
Main server, FreeBSD, also php 4.3
Running identical Apache setups and Identical php setups.
The staging server is only accessible behind our local firewall and does
not run https. The Main
Lets say I'm trying to extract some data from an HTML document. I want
to get the values of the 'src' attributes of various tags.
For example-
img src=http://www.yahoo.com;
here's the pattern I've been trying-
/\bsrc=(['|])[^\\1]*[\\1]/im
Basically, match the 'src=' followed by some type of
including the quotes, so I'm
really not sure what's failing.
Thanks-
Thaddeus
Ford, Mike [LSS] wrote:
On 21 August 2003 17:03, Thaddeus J. Quintin wrote:
Lets say I'm trying to extract some data from an HTML
document. I want
to get the values of the 'src' attributes of various tags.
For example-
img
.
not the prettiest answer, but I put good comments around it!
Thaddeus
Scott Fletcher wrote:
Try parsing it as a string where the double quote would become a string.
See if that help. (Parse the whole characters into strings then find the
double quote.)
Thaddeus J. Quintin [EMAIL PROTECTED] wrote
I'm looking to replace the 'nth' instance of an expression within a string.
Example (very simple)-
$string=My mom can beat up your mom and your mom's dog;
$pattern=mom;
$replacement=dad;
I want to be able to replace any particular instance of the pattern
within that string. I was getting ready
I'm looking to replace the 'nth' instance of an expression within a string.
Example (very simple)-
$string=My mom can beat up your mom and your mom's dog;
$pattern=mom;
$replacement=dad;
I want to be able to replace any particular instance of the pattern
within that string. I was getting ready
Perfect solution.
Thanks, I don't know how I overlooked the preg_replace_callback
function. That's exactly what I needed.
Thaddeus
CPT John W. Holmes wrote:
From: Thaddeus J. Quintin [EMAIL PROTECTED]
I'm looking to replace the 'nth' instance of an expression within a
string.
Example (very
Hello-
I'm working on a site where users have the option to type HTML code into
a textarea, or upload HTML code from a local file which is then
displayed in the text area.
The obvious problem is that an uploaded file that contains a closing tag
for a textarea can wreak havoc and eat up the
. Holmes wrote:
From: Thaddeus J. Quintin [EMAIL PROTECTED]
I'm working on a site where users have the option to type HTML code into
a textarea, or upload HTML code from a local file which is then
displayed in the text area.
The obvious problem is that an uploaded file that contains a closing tag
Thanks everybody!
Looks like I was just thinking about the problem too hard.
Thaddeus
John W. Holmes wrote:
Thaddeus J. Quintin wrote:
CPT John W. Holmes wrote:
--SNIP--
Try this:
textarea name=textThis is lt;somegt; text/textarea
If you submit that text and then print $_REQUEST
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