This should be trivial, but apparently not -- or maybe I just need more
caffeine. My searches have come up empty.
I am trying to get not only the original file name on uploads, but also
the original directory on the client machine as well.
The purpose is for users who make a mistake on
On Mon, Oct 6, 2008 at 11:48 AM, J. Hill [EMAIL PROTECTED] wrote:
This should be trivial, but apparently not -- or maybe I just need more
caffeine. My searches have come up empty.
I am trying to get not only the original file name on uploads, but also the
original directory on the client
Any suggestions?
Yes, keep your pesky nose out. It's my machine and my file system is
none of your business. Simply, you get whatever is in $_FILES and
that's it. From memory thats the filename, the path to it on your
machine, and size info. And maybe something else. Try print_r()ing
$_FILES,
-Original Message-
From: J. Hill [mailto:[EMAIL PROTECTED]
Sent: Monday, October 06, 2008 10:48 AM
To: php-general@lists.php.net
Subject: [PHP] How to capture origional client machine _directory_ and
file name on uploads?
This should be trivial, but apparently not -- or maybe I
[Sorry Nathan.]
Yes, I should have said autopopulate. And from what I have found,
you're right; it does appear java applets can do it, but I had hoped to
avoid that option.
Eric Butera -- The file upload will only exist in the specified temp
directory . . ..
Perhaps I should have explained
On Mon, 2008-10-06 at 12:35 -0400, J. Hill wrote:
[Sorry Nathan.]
Yes, I should have said autopopulate. And from what I have found,
you're right; it does appear java applets can do it, but I had hoped to
avoid that option.
Eric Butera -- The file upload will only exist in the
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