Re: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-27 Thread Burhan Khalid
Brian Dunning wrote: How do I check for the presence of an optional $_GET param without throwing a Notice: Undefined index when the param is not present? Tried all three of these, they all produce the Notice when the param is not passed: if ($_GET['id']) if ($_GET['id'] != ) if (isset

[PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread Brian Dunning
How do I check for the presence of an optional $_GET param without throwing a Notice: Undefined index when the param is not present? Tried all three of these, they all produce the Notice when the param is not passed: if ($_GET['id']) if ($_GET['id'] != ) if (isset $_GET['id']) -- PHP General

Re: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread Richard Davey
Hello Brian, Wednesday, May 26, 2004, 4:01:30 PM, you wrote: BD How do I check for the presence of an optional $_GET param without BD throwing a Notice: Undefined index when the param is not present? BD Tried all three of these, they all produce the Notice when the param is BD not passed: BD

Re: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread John W. Holmes
From: Brian Dunning [EMAIL PROTECTED] How do I check for the presence of an optional $_GET param without throwing a Notice: Undefined index when the param is not present? Tried all three of these, they all produce the Notice when the param is not passed: if ($_GET['id']) if

Re: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread Daniel Clark
if (isset( $_GET['id'])) How do I check for the presence of an optional $_GET param without throwing a Notice: Undefined index when the param is not present? Tried all three of these, they all produce the Notice when the param is not passed: if ($_GET['id']) if ($_GET['id'] != ) if (isset

RE: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread Rick Fletcher
How do I check for the presence of an optional $_GET param without throwing a Notice: Undefined index when the param is not present? Tried all three of these, they all produce the Notice when the param is not passed: if ($_GET['id']) if ($_GET['id'] != ) if (isset $_GET['id'])

Re: [PHP] How to check for a $_GET without throwing a Notice?

2004-05-26 Thread Tyler Replogle
aslo you could change it to something else like this $_GET['id'] = $id; if (!$id) { // whatever you want to happen put here } From: Daniel Clark [EMAIL PROTECTED] Reply-To: Daniel Clark [EMAIL PROTECTED] To: Brian Dunning [EMAIL PROTECTED],[EMAIL PROTECTED] [EMAIL PROTECTED] Subject: Re: [PHP]