On Wed, August 1, 2007 11:52 am, Mark Summers wrote:
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
What did you get?
What did you expect?
Do you have ANY idea how floats are actually represented internally in
every computer language? [*]
If you
Richard's right. You get the same result if you do the equivalent in
ASP.
Regards,
Bruce
Richard Lynch [EMAIL PROTECTED] 8/08/2007 3:29:16 p.m.
On Wed, August 1, 2007 11:52 am, Mark Summers wrote:
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
Those numbers must fall on the other side of the number. E.g.,
75.81 == 75.8100011 (etc)
so you get the expected results.
Mark Summers wrote:
I like to think that I'm reasonably aware of the limitations of floating
point (famous last words).
To my mind, the ridiculousness (probably
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
--
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To unsubscribe, visit: http://www.php.net/unsub.php
On 8/1/07, Mark Summers [EMAIL PROTECTED] wrote:
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
What exactly were you expecting it to do? :)
Very weird and counter intuitive. Looking at the php manual, I see this:
Converting to integer from floating point:
When converting from float to integer, the number will be rounded towards
zero.
But you'd think the multiplication would happen before the rounding.
if you do:
$a = ceil(75.82
Probably return 7582 instead of 7581.
= = = Original message = = =
On 8/1/07, Mark Summers [EMAIL PROTECTED] wrote:
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit:
It is most definitely not if what you want is the square root, or the
hyperbolic cosine or any other of a zillion things.
- Original Message -
From: Mark Summers [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Wednesday, August 01, 2007 6:52 PM
Subject: [PHP] Loss of precision
Internally, 75.82 can't be stored exactly, so 75.82 * 100 is probably
7581.92 rather than the expected integer value of 7582. So intval is
behaving properly. Sounds like you want intval(round($a));
[EMAIL PROTECTED] wrote:
Very weird and counter intuitive. Looking at the php manual, I see
On 8/1/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Probably return 7582 instead of 7581.
= = = Original message = = =
On 8/1/07, Mark Summers [EMAIL PROTECTED] wrote:
This sort of thing really isn't helpful...
?php
$a = 75.82 * 100;
echo intval($a);
?
--
PHP General
Roberto Mansfield wrote:
Internally, 75.82 can't be stored exactly, so 75.82 * 100 is probably
7581.92 rather than the expected integer value of 7582. So intval is
behaving properly. Sounds like you want intval(round($a));
[EMAIL PROTECTED] wrote:
Very weird and counter intuitive.
I like to think that I'm reasonably aware of the limitations of floating
point (famous last words).
To my mind, the ridiculousness (probably not a word) of the example is
highlighted by the fact that 75.81 and 75.83 work perfectly.
Roberto Mansfield wrote:
Internally, 75.82 can't be stored
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