Alright! Found the problem! Faulty script written that come before this
script where $$var come into play. At least, it wasn't me, it was the other
programmer's error. :-)
"Scott Fletcher" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Interesting! Look l
What docs at php.net? under variable, predefine variable or what?
"Andrey Hristov" <[EMAIL PROTECTED]> wrote in message
002601c22cd0$b1995170$1601a8c0@nik">news:002601c22cd0$b1995170$1601a8c0@nik...
> Variable variable. Read the docs.
>
> $v = 'foo';
> $foo = 'bar';
> echo $$v;
>
> Regards,
> An
ned.php
>
> Regards
> Joakim Andersson
>
>
> > -Original Message-
> > From: Scott Fletcher [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, July 16, 2002 3:54 PM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] Purpose of $$var ?
> >
> >
>From: Scott Fletcher [mailto:[EMAIL PROTECTED]]
>Sent: Tuesday, July 16, 2002 9:54 AM
>To: [EMAIL PROTECTED]
>Subject: [PHP] Purpose of $$var ?
>
>
>The script was working great before PHP 4.2.x and not after that. So, I
>looked through the code and came upon this variabl
/language.variables.predefined.php
Regards
Joakim Andersson
> -Original Message-
> From: Scott Fletcher [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 16, 2002 3:54 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Purpose of $$var ?
>
>
> The script was working great before
Interesting! Look like the 2nd "$" is decomissioned and is reserve for
something in the future or something. Just like the "_" is when it come
with $_POST as an example. That would explain why it doesn't work with PHP
4.2.x & up.
"Andrey Hristov" <[EMAIL PROTECTED]> wrote in message
002601c22c
Variable variable. Read the docs.
$v = 'foo';
$foo = 'bar';
echo $$v;
Regards,
Andrey
P.S.
Sometimes {} are used : ${$v}
"Scott Fletcher" <[EMAIL PROTECTED]> wrote in message
news:<[EMAIL PROTECTED]>...
> The script was working great before PHP 4.2.x and not after that. So, I
> looked thro
The script was working great before PHP 4.2.x and not after that. So, I
looked through the code and came upon this variable, "$$var". I have no
idea what the purpose of the double "$" is for a variable. Anyone know?
--clip--
$var = "v".$counter."_high_indiv";
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