You are testing unset variables. This will work as you expect:
<?php
$a = 1;
$id = "outside";
if ($a == 0) {
$b = 1;
$id = "a";
}
elseif (isset($b) && $b == 0) {
$c = 1;
$id = "b";
}
elseif (isset($c) && $c == 0){
$d = 1;
$id = "c";
}
echo "ID = $id<br>"; //Output is "b"...WHY?? It should be "outside"...
?>
Choy, Wai Yew wrote:
Hi gurus,
I've the following piece of PHP code....It is a simple logic but I can't
get it right....The output result of $id is "b"!!...It should be
"outside", right??
I think it is the variable $b....Coz' it depend on the previous check (
if ($a == 0) ) for the value... If this is the case, how can I get this
logic works??
Thanks a million,
Choy
<?php
$a = 1;
$id = "outside";
if ($a == 0) {
$b = 1;
$id = "a";
}
elseif ($b == 0) {
$c = 1;
$id = "b";
}
elseif ($c == 0){
$d = 1;
$id = "c";
}
echo "ID = $id<br>"; //Output is "b"...WHY?? It should be "outside"...
?>
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