[PHP] Re: parse_str() expects parameter 1 to be string, array given

2009-10-19 Thread Al
Use var_dump() and see exactly what your variable is. You can be certain it is really an array; the parser is good about such warnings. Fix the source of the variable given to parse_str. Julian Muscat Doublesin wrote: Hello* *Everyone, I am geetting the error below. Can you please guide me

[PHP] Re: parse_str()

2003-04-02 Thread Ron Rudman
I think you mean: $example_string = '?action=kickitem=me'; Jose [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] I might be wrong here, but with the code below I would expect $_GET to be filled and the script to output the next line: ?php $example_string = 'action=kickitem=me';

Re: [PHP] Re: parse_str()

2003-04-02 Thread Rasmus Lerdorf
Jose [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] I might be wrong here, but with the code below I would expect $_GET to be filled and the script to output the next line: ?php $example_string = 'action=kickitem=me'; parse_str($example_string); var_dump($_GET);