Use var_dump() and see exactly what your variable is.
You can be certain it is really an array; the parser is good about such
warnings.
Fix the source of the variable given to parse_str.
Julian Muscat Doublesin wrote:
Hello* *Everyone,
I am geetting the error below. Can you please guide me
I think you mean:
$example_string = '?action=kickitem=me';
Jose [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I might be wrong here, but with the code below I would expect $_GET to be
filled and the script to output the next line:
?php
$example_string = 'action=kickitem=me';
Jose [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I might be wrong here, but with the code below I would expect $_GET to be
filled and the script to output the next line:
?php
$example_string = 'action=kickitem=me';
parse_str($example_string);
var_dump($_GET);
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