Victor Spng Arthursson wrote:
Have been playing around a bit with this code, but I can't get it to
work with international characters For example, if I feed my function:
function split_bokid($bokid)
{
if
(preg_match('/^([a-z]{2,3})([0-9]{4,5}(\-[0-9]{1,2}){0,1})$/
2004-01-22 kl. 10.40 skrev Dagfinn Reiersl:
I assume you mean:
$test = split_bokid(12345);
Yes!
I don't know. It works fine on my computer. The letters display
correctly on the command line and even in Mozilla.
Hmmm try the following:
maybe this work:
replace the special-characters first, eg.:
$bokid = str_replace(å, _, $bokid);
and replace them back after preg_match
or try the preg_match with the hexcode of this special chars:
\xhh character with hex code hh
(http://ch2.php.net/manual/de/pcre.pattern.syntax.php)
g. martin
2004-01-20 kl. 10.41 skrev Dagfinn Reiersl:
[EMAIL PROTECTED] wrote:
$string = 'ab12345-1';
if (preg_match('/^([a-z]{2,3})([0-9]{4,5}(\-[0-9]{1,2}){0,1})$/i',
$string,
$m='')) {
echo $m[1]; // - ab
echo $m[2]; // - 12345-1
}
g. martin luethi
You can replace {0,1} with a question mark and
Hi!
Anyone who could help me with this regexp problem?
I want to verify that a string is made up of 2-3 letters, (a-z + åäö,
A-Z + ÅÖÄ), directly followed by 4 or 5 digits, which could, but may
not, be followed by a minus and one or two digits.
Examples of valid strings:
abc12345
ABC12345
$string = 'ab12345-1';
if (preg_match('/^([a-zåäö]{2,3})([0-9]{4,5}(\-[0-9]{1,2}){0,1})$/i',
$string,
$m='')) {
echo $m[1]; // - ab
echo $m[2]; // - 12345-1
}
g. martin luethi
Tue, 20 Jan 2004 09:59:37 +0100 Victor Spång Arthursson [EMAIL PROTECTED]:
Hi!
Anyone who could help me with
[EMAIL PROTECTED] wrote:
$string = 'ab12345-1';
if (preg_match('/^([a-zåäö]{2,3})([0-9]{4,5}(\-[0-9]{1,2}){0,1})$/i',
$string,
$m='')) {
echo $m[1]; // - ab
echo $m[2]; // - 12345-1
}
g. martin luethi
You can replace {0,1} with a question mark and [0-9] with \d (digit).
Also, and I
think
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