"Jacky@lilst" wrote:
People
If I run a sniplet like this:
**
$query="select name from foo";
$result= mysql_query($query);
while($row = mysql_fetch_row($result))
stuff...to display record found
...
***
what am I suppose to do if
People
If I run a sniplet like this:
**
$query="select name from foo";
$result= mysql_query($query);
while($row = mysql_fetch_row($result))
stuff...to display record found
...
***
what am I suppose to do if I also want the code to be able to
On Tue, 6 Mar 2001 06:36, [EMAIL PROTECTED] wrote:
People
If I run a sniplet like this:
**
$query="select name from foo";
$result= mysql_query($query);
while($row = mysql_fetch_row($result))
stuff...to display record found
...
***
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