Hi,
Running the code below, shows an errror in line 2 as expected.
How do i get the linenumber of the function call? 3 here.
?
function test($x){if($x!='a')trigger_error('error: call test with argument 1
equals a',E_USER_ERROR);}
test('b');
?
Best regards,
Bas
--
PHP General Mailing List
Use the predefined constant:
__LINE__
Regards,
Michael Egan
-Original Message-
From: Bas Jobsen [mailto:[EMAIL PROTECTED]
Sent: 16 June 2003 12:50
To: PHP General
Subject: [PHP] error reporting linenumber and filename[Scanned]
Hi,
Running the code below, shows an errror in line 2
[mailto:[EMAIL PROTECTED]
Sent: 16 June 2003 13:14
To: Michael Egan
Subject: Re: [PHP] error reporting linenumber and filename[Scanned]
Dear Michael,
Thanks for your respons, maybe i don't inderstand your solution but:
1function line()
2{
3 echo __line__;
4}
5line();
will print 3
-Original Message-
From: Bas Jobsen [mailto:[EMAIL PROTECTED]
Sent: 16 June 2003 14:39
I'm not sure that there is a way beyond this to show the
line within the
function but I don't see that this would be necessary - at
least not for
resolving errors.
i'm building a class
Not possible with current php
Bas Jobsen wrote:
Hi,
Running the code below, shows an errror in line 2 as expected.
How do i get the linenumber of the function call? 3 here.
?
function test($x){if($x!='a')trigger_error('error: call test with argument 1
equals a',E_USER_ERROR);}
test('b');
?
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