The while statement is only executing correctly for the first run through
the foreach loop. Why?
Thanks,
loop
foreach($desc as $key=$value) {
printf(Show %s Description select name='show%sDesc', $key, $key);
echo option value = ''/option;
while($row = mysql_fetch_row($show_names))
From: James Brennan [EMAIL PROTECTED]
Sent: Tuesday, January 07, 2003 8:29 PM
Subject: [PHP] help - WHILE in FOREACH
The while statement is only executing correctly for the first run through
the foreach loop. Why?
Thanks,
loop
foreach($desc as $key=$value) {
printf(Show %s Description
Is this your exact code? I ask, because the following should generate a parse error:
echo option value = ''/option;
You have 3 double-quotes ().
- Original Message -
From: James Brennan [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, January 07, 2003 7:29 PM
Subject: [PHP] help
The second set of quotes is actualy two single quotes with nothing
in-between.
.loop
From: Rick Emery [EMAIL PROTECTED]
Reply-To: Rick Emery [EMAIL PROTECTED]
To: James Brennan [EMAIL PROTECTED],[EMAIL PROTECTED]
Subject: Re: [PHP] help - WHILE in FOREACH
Date: Tue, 7 Jan 2003 20:18:08 -0600
On Tue, 7 Jan 2003, James Brennan wrote:
The while statement is only executing correctly for the first run through
the foreach loop. Why?
It's /real/ hard to tell when you don't give any context or otherwise
explain what it is you want to achieve. Since the code in fact executes
correctly, we
My appologies for the lack of explicit information. Thank you for taking the
time to write a reply. That is exactly what I needed to know.
Thanks again,
James
From: Chris Wesley [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Re: [PHP] help - WHILE in FOREACH
Date: Tue, 7 Jan 2003 18:49:53
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