On 19 June 2009 19:53, Ashley Sheridan advised:
On Fri, 2009-06-19 at 12:36 +0100, Ford, Mike wrote:
On 18 June 2009 20:25, LAMP advised:
using !empty() instead isset() will work if you don't care for PHP
Notice: Undefined variable... If you want to avoid PHP Notice
you have
to use both:
How does echoing back to the page make it vulnerable? This does not go to a
DB if that makes any difference.
Gary
Paul M Foster pa...@quillandmouse.com wrote in message
news:20090621032151.gb14...@quillandmouse.com...
On Sat, Jun 20, 2009 at 12:20:56PM +0100, Ashley Sheridan wrote:
On Sat,
On Sun, 2009-06-21 at 13:57 -0400, Gary wrote:
How does echoing back to the page make it vulnerable? This does not go to a
DB if that makes any difference.
Gary
Paul M Foster pa...@quillandmouse.com wrote in message
news:20090621032151.gb14...@quillandmouse.com...
On Sat, Jun 20,
On Sat, 2009-06-20 at 00:19 -0400, Paul M Foster wrote:
On Fri, Jun 19, 2009 at 07:52:40PM +0100, Ashley Sheridan wrote:
On Fri, 2009-06-19 at 12:36 +0100, Ford, Mike wrote:
On 18 June 2009 20:25, LAMP advised:
using !empty() instead isset() will work if you don't care for PHP
Waynn Lue wrote:
I notice that you're checking $_POST['mort'] but you're echoing $mort,
is that your actual code?
That was my observation as well. Is $mort = $POST['mort']; being
set somewhere else or not? If not, how is your script supposed to
know what value $mort should be?
And, what the
Yes... I echo the code onto the page as well as sending out the message.
The echo is sort of a thank you page, this is what you submitted. A
message, which is not going into a DB, is also emailed to the submitter and
cleint.
Gary
Waynn Lue waynn...@gmail.com wrote in message
On Sat, Jun 20, 2009 at 12:20:56PM +0100, Ashley Sheridan wrote:
On Sat, 2009-06-20 at 00:19 -0400, Paul M Foster wrote:
On Fri, Jun 19, 2009 at 07:52:40PM +0100, Ashley Sheridan wrote:
On Fri, 2009-06-19 at 12:36 +0100, Ford, Mike wrote:
On 18 June 2009 20:25, LAMP advised:
On 18 June 2009 20:25, LAMP advised:
using !empty() instead isset() will work if you don't care for PHP
Notice: Undefined variable... If you want to avoid PHP Notice
you have
to use both:
$msg.= (isset($_POST['mort']) and !empty($_POST['mort'])) ? The
mortgage amount is $mort\n : ;
On Fri, 2009-06-19 at 12:36 +0100, Ford, Mike wrote:
On 18 June 2009 20:25, LAMP advised:
using !empty() instead isset() will work if you don't care for PHP
Notice: Undefined variable... If you want to avoid PHP Notice
you have
to use both:
$msg.= (isset($_POST['mort']) and
On Fri, Jun 19, 2009 at 07:52:40PM +0100, Ashley Sheridan wrote:
On Fri, 2009-06-19 at 12:36 +0100, Ford, Mike wrote:
On 18 June 2009 20:25, LAMP advised:
using !empty() instead isset() will work if you don't care for PHP
Notice: Undefined variable... If you want to avoid PHP Notice
I have a form that gives the submitter a choice or either one set of
questions, or another. I am still getting the message even if the input was
left blank. So on the line below,
$msg.= isset($_POST['mort']) ? The mortgage amount is $mort\n : ;
I get
The mortgage amount is
What am I
2009/6/18 Gary gwp...@ptd.net:
I have a form that gives the submitter a choice or either one set of
questions, or another. I am still getting the message even if the input was
left blank. So on the line below,
$msg.= isset($_POST['mort']) ? The mortgage amount is $mort\n : ;
I get
The
Use !empty($_POST['mort']) instead of isset() for form input since the
form will still set an empty value if left blank.
Gary wrote:
I have a form that gives the submitter a choice or either one set of
questions, or another. I am still getting the message even if the input was
left blank. So
Steve wrote:
Use !empty($_POST['mort']) instead of isset() for form input since the
form will still set an empty value if left blank.
Gary wrote:
I have a form that gives the submitter a choice or either one set of
questions, or another. I am still getting the message even if the
input was
I notice that you're checking $_POST['mort'] but you're echoing $mort,
is that your actual code?
On 6/18/09, Gary gwp...@ptd.net wrote:
I have a form that gives the submitter a choice or either one set of
questions, or another. I am still getting the message even if the input was
left blank.
Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu.
Date: Thu, 18 Jun 2009 20:07:09 +0100
From: stut...@gmail.com
To: gwp...@ptd.net
CC: php-general@lists.php.net
Subject: Re: [PHP] isset question
2009/6/18 Gary gwp...@ptd.net:
I have a form that gives the submitter
Hello Jason,
Sunday, February 15, 2004, 7:44:06 PM, you wrote:
I feel the book you're learning from might not be the best out there!
Especially as it uses the horrible if : else : endif notation,
includes code on the same line as the PHP tags themselves
JW What is horrible about that style?
On 15 February 2004 18:30, Richard Davey wrote:
I feel the book you're learning from might not be the best out there!
Especially as it uses the horrible if : else : endif notation,
I'd have to disagree with you on that one -- personally I think that's a very elegant
and useful syntax, and all
On Monday 16 February 2004 18:14, Richard Davey wrote:
Consistency.
With what? With whose idea of style/formatting?
I doubt you will find consistency in the real between different
programmers/organisations. If such consistency was there then PHP would've
have only had to support a single
Hello Jason,
Monday, February 16, 2004, 2:21:01 PM, you wrote:
Consistency.
JW With what? With whose idea of style/formatting?
If you hadn't chopped off the rest of my paragraph you'd have the
answer.
JW I doubt you will find consistency in the real between different
JW
The following script is from Kevin Yank's book (Sitepoint).
When I test it _without_ entering a name in the text box and hit submit, the
_next_ page
loads - however the same page should load beacuse of the conditional
if (!isset($name) ):
.
If I replace
!isset()
with
empty()
Hello Anthony,
Sunday, February 15, 2004, 4:43:12 PM, you wrote:
AR Why doesn't the call to !isset() with the negation mark loads the next page
AR when a name is not entered?
Because it's using isset() in the wrong capacity.
isset() does not check to see if a variable HAS a value, it checks to
- Original Message -
From: Richard Davey [EMAIL PROTECTED]
Hello Anthony,
I feel the book you're learning from might not be the best out there!
Especially as it uses the horrible if : else : endif notation,
includes code on the same line as the PHP tags themselves and is
teaching
On Monday 16 February 2004 02:30, Richard Davey wrote:
I feel the book you're learning from might not be the best out there!
Especially as it uses the horrible if : else : endif notation,
includes code on the same line as the PHP tags themselves
What is horrible about that style? IMO doing
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