Re: [PHP] set variable to go outside scope

2006-01-05 Thread Mike Tuller
It's more like this: if { $x=1; echo $x; } elseif { echo $x; } On Jan 5, 2006, at 1:51 PM, Jay Blanchard wrote: [snip] The list listing is in an if/elseif statement where if something is set, display the table that has the data, and elseif you click on the delete button

RE: [PHP] set variable to go outside scope

2006-01-05 Thread Jay Blanchard
[snip] The list listing is in an if/elseif statement where if something is set, display the table that has the data, and elseif you click on the delete button, you would delete the data in the row of the table that is is the if statement. One part of the data is in the if scope, and the oth

Re: [PHP] set variable to go outside scope

2006-01-05 Thread Mike Tuller
The list listing is in an if/elseif statement where if something is set, display the table that has the data, and elseif you click on the delete button, you would delete the data in the row of the table that is is the if statement. One part of the data is in the if scope, and the other is i

RE: [PHP] set variable to go outside scope

2006-01-05 Thread Jay Blanchard
[snip] They key I am using to find the record I want to delete is the the $row[id], but that is out of the scope of where the variable is set. Is there a way to set a variable so that it goes outside the scope? [/snip] What do you mean by "out of the scope of where the variable is set"? If the

[PHP] set variable to go outside scope

2006-01-05 Thread Mike Tuller
I have a table listing items in a database, and have a delete button next to each item, and I want to be able to click on the delete and delete only that record in the database and then reload the page where it would display the updated information. Here is part of the code I have.