Re: [PHP] subtitute of mysql_error()

2007-08-07 Thread Richard Lynch
Whatever made you think mysql_error() wasn't working, that was wrong. Because mysql_error() works just fine. On Wed, August 1, 2007 1:09 am, Patrik Hasibuan wrote: Dear my friends What is the substitute of mysql_error() ? This line of my code does not work anymore:

[PHP] subtitute of mysql_error()

2007-08-01 Thread Patrik Hasibuan
Dear my friends What is the substitute of mysql_error() ? This line of my code does not work anymore: $hslgbr=mysql_query($sqlgbr,$konek) or die ( mysql_error() ); Thank you very much in advance. -- Patrik Hasibuan [EMAIL PROTECTED] Junior Programmer -- PHP General

Re: [PHP] subtitute of mysql_error()

2007-08-01 Thread Stut
Patrik Hasibuan wrote: Dear my friends What is the substitute of mysql_error() ? This line of my code does not work anymore: $hslgbr=mysql_query($sqlgbr,$konek) or die ( mysql_error() ); Thank you very much in advance. In what way does it not work anymore? The code