2008. 03. 28, péntek keltezéssel 12.28-kor Jason Pruim ezt írta:
> Hi everyone :) Happy friday to all of you!
>
> Here's my issues, I am attempting to echo the results of mysqli query
> out to my script just so I can make sure it's working right, what I'm
> hoping to do in the long run is comp
On Fri, Mar 28, 2008 at 12:28 PM, Jason Pruim <[EMAIL PROTECTED]> wrote:
[snip!]
>
> $oldpasswordquery = "SELECT loginPassword, Record FROM current WHERE
> loginPassword='{$oldPassHash}' AND Record='{$Record}'";
> $chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or
> die("Sorry read
On Fri, Mar 28, 2008 at 12:58 PM, Jason Pruim <[EMAIL PROTECTED]> wrote:
>
>
> On Mar 28, 2008, at 12:40 PM, Eric Butera wrote:
> > On Fri, Mar 28, 2008 at 12:28 PM, Jason Pruim <[EMAIL PROTECTED]>
> > wrote:
> >> $chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or
> >> die("Sorry r
On Mar 28, 2008, at 12:40 PM, Eric Butera wrote:
On Fri, Mar 28, 2008 at 12:28 PM, Jason Pruim <[EMAIL PROTECTED]>
wrote:
$chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or
die("Sorry read failed: ". mysqli_error($chpwpostlink));
$chpwresult = $chpwold[0];
Why would you pump that
That's because your loginpassWord is in another array.
try $chpwrow[0]['loginPassword']
-Mensagem original-
De: Jason Pruim [mailto:[EMAIL PROTECTED]
Enviada em: sexta-feira, 28 de março de 2008 13:29
Para: [php] PHP General List
Assunto: [PHP] why won't my arra
On Fri, Mar 28, 2008 at 12:28 PM, Jason Pruim <[EMAIL PROTECTED]> wrote:
> $chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or
> die("Sorry read failed: ". mysqli_error($chpwpostlink));
> $chpwresult = $chpwold[0];
Why would you pump that into an array instead of just calling it
resu
Hi everyone :) Happy friday to all of you!
Here's my issues, I am attempting to echo the results of mysqli query
out to my script just so I can make sure it's working right, what I'm
hoping to do in the long run is compare what was typed in a text box
to this info... It's for verifying a ol
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