On Saturday 15 November 2003 02:38, Teren wrote:
Sorry, i copied a little extra stuff from console. This is what it is,
Anyways, it works fine if I put 0 in for 1 on line 9 where it uses the
rand(), but it include 0 and I can't have 0. Is there some way to fix that?
If you need to see the demo
You're code doesn't make sense. You're looking for 3 random numbers, between
1 and 3 inclusive. Umm.. 1,2,3.
Do you want them in a random order, or something?
Maybe the upper limit of rand() and how many numbers you're looking for
($n), should be different??
---John Holmes...
- Original
) {
set_num();
}
?
- Original Message -
From: CPT John W. Holmes [EMAIL PROTECTED]
To: Teren [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, November 14, 2003 1:28 PM
Subject: Re: [PHP] Random Function
You're code doesn't make sense. You're looking for 3 random numbers,
between
1
Teren wrote:
Anyways, it works fine if I put 0 in for 1 on line 9 where it
uses the rand(), but it include 0 and I can't have 0.
Why not just change the following:
if($ran == $sh) {
$add = no;
}
to:
if($ran == $sh || $ran == 0) {
$add = no;
}
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