Re: [PHP] SQL help?

2009-05-18 Thread Marcus Gnaß
Skip Evans wrote: > Hey all, > > I have a SQL requirement I'm not quite sure how to compose. > > I have two tables, shows, and shows_dates. It's a one to many > relationship where there is a single entry in shows and multiple entries > in shows_dates that list each date and time for a play produc

Re: [PHP] SQL help

2004-02-10 Thread Marc Greenstock
That works well, Thanks all. "Warren Vail" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > The problem is you are using a hard join which will only return rows where > there are matching entries in both tables. What you probably want is called > a left join, however you have a fur

RE: [PHP] SQL help

2004-02-10 Thread Larry Brown
Correct me if I'm wrong...PLEASE.. but, I believe you are looking for... SELECT * FROM user_data left join image_data on user_data.User_ID=image_data.User_ID where image_data.Default_Img = 'Yes' GROUP BY user_data.User_ID I haven't used enum('Yes','No') so I'm taking your word for the fact that y

Re: [PHP] SQL help

2004-02-10 Thread Marc Greenstock
The DB is MySQL 4.0.16, all tables are MyISAM "Martin Towell" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > You'll need to do a left/right outer join. > > as you didn't say which database you're using, I'll give this back to you to > do some reading up on how to do it... > > HTH

RE: [PHP] SQL help

2004-02-10 Thread Vail, Warren
The problem is you are using a hard join which will only return rows where there are matching entries in both tables. What you probably want is called a left join, however you have a further complication. You have to have an image row to have a image_data.Default_Img = 'Yes'. So this query is re

RE: [PHP] SQL help

2004-02-10 Thread Martin Towell
You'll need to do a left/right outer join. as you didn't say which database you're using, I'll give this back to you to do some reading up on how to do it... HTH Martin > -Original Message- > From: Marc Greenstock [mailto:[EMAIL PROTECTED] > Sent: Wednesday, 11 February 2004 1:53 PM > T

Re: [PHP] sql help ?

2002-06-18 Thread w . w . w
> or one line for each sess_id with only one row: > select * from tracker where count(sess_id)=1 and day='1' and month=' > ".$month." ' group by sess_id; sorry that was wrong! correct: select * from tracker where day='1' and month=' ".$month." ' group by sess_id having count(sess_id)=1; michi

Re: [PHP] sql help ?

2002-06-18 Thread w . w . w
> select * from tracker where day='1' and month=' ".$month." ' XXX"; > > XXX = but donot return values with the same value in the "sess_id" field > > what should XXX be ? one line for each sess_id select * from tracker where day='1' and month=' ".$month." ' group by sess_id; or one