Change your die() call to this:
die(mysql_error())
so you can actually see what is going on.
-Rasmus
On Mon, 20 May 2002, Php Developers wrote:
> This command just dies!
>
> I have checked sql connection ... ok
> the insert into line ... ok
>
> Pfft it just don't wanna work
>
>
>
> $answe
> INSERT INTO prizeline (id, email, name, address, answers,
> date) VALUES ('', '[EMAIL PROTECTED]', 'newman',
> '12 Newman ave Auckland', 'In Season, James, John', 'Monday
> 20th of May 2002 10:22:05 AM')There has been an error
If you want 'id' to be assigned by the database (I'm assumi
PD> $answers="$band, $middlename, $pot";
PD> $date=date ("l dS of F Y h:i:s A");
PD> $sql = "INSERT INTO prizeline (id, email, name, address, answers, date) VALUES
('', '$email', '$name', '$address', '$answers', '$date')";
PD> echo $sql;
PD> mysql_query($sql) or die ("There has been an e
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