Re: [PHP] Debugging problems

2001-05-22 Thread Chris Lee
best bet is to put some error checking in. function _check_db($query = '', $line = '') { if ( mysql_errno() ) { echo Error: Problem with DataBase : {$GLOBALS['db_database']}br\n; echo Error: . mysql_errno() . ':' . mysql_error() . br\n; echo Query: $querybr\n; echo Line :

Re: [PHP] debugging problems

2001-05-18 Thread elias
You forgot to select the database! mysql_select_db($db_name); -elias http://www.eassoft.cjb.net Taline Makssabo [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... This is a program i wrote to get some information at keep track with some stats. I am very new at

RE: [PHP] debugging problems

2001-05-18 Thread Don Read
On 18-May-01 Taline Makssabo wrote: This is a program i wrote to get some information at keep track with some stats. I am very new at this so bare with meI keep on getting this Warning: Warning: Supplied argument is not a valid MySQL result resource in