> How can the resource be invalid if I'm getting the results back? I'd
> appreciate any explaination.
What results are you getting?...
> $connection_id = @mysql_connect ('localhost', 'root') or die('No
> connection.');
> $database_id = @mysql_select_db ('cgcms', $connection_id) or die(
>From experience with oracle, desc only works in an sql prompt, not through
code. So use the more lengthy method
in mysql:
SHOW FIELDS FROM $table_name
in oracle:
SELECT c.column_name, c.data_type, c.data_length, c.data_precision,
c.data_scale, c.nullable FROM sys.dba_tab_colum
- Original Message -
From: "David Robley" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; "PHP General" <[EMAIL PROTECTED]>
Sent: Wednesday, June 27, 2001 8:47 AM
Subject: Re: [PHP] Strange error on mysql_fetch_array
> On Wed, 27 Jun 2001 06:31, [
On Wed, 27 Jun 2001 06:31, [EMAIL PROTECTED] wrote:
> The following code fragment works properly, in that I get the output
> I'm expecting. However, if I don't disable error messages with @, I get
> an error message from PHP saying: "Warning: Supplied argument is not a
> valid MySQL result resourc
dunno
but my it's just failing at the mysql_connect()
shouldn't you specify the password too?
<[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> The following code fragment works properly, in that I get the output I'm
> expecting. However, if I don't disable e
In article <046401c0fee3$a6c789e0$6401a8c0@Lynchux100>,
[EMAIL PROTECTED] ("Richard Lynch") wrote:
> > $result_id = @mysql_query("DESC $table_name $field_name");
>
> I don't think "DESC $table_name $field_name" is valid SQL, is it?...
>
> DESC is DESCENDING in an ORDER BY clause...
>
> Pe
6 matches
Mail list logo
