On 06/23/2010 09:44 PM, Steven A. DuChene wrote:
My problem is I want to be able to pick up $2 from the command line invocation
of my bash script for the desired password and then pass that into the one
line
perl piece. But with all of the single quotes, double quotes, back ticks and
etc. I
I think that did the trick Eric.
Thanks!
-Original Message-
From: Eric Shubert e...@shubes.net
Sent: Jun 24, 2010 11:02 AM
To: plug-discuss@lists.plug.phoenix.az.us
Subject: Re: how to reference bash variables inside perl script inside bash
script?
Stuff inside of single quotes
On 06/23/2010 09:44 PM, Steven A. DuChene wrote:
The core part of the script I am having a problem with looks like:
#!/bin/bash
OPASS=$2
PASS=`perl -e 'print(userPassword:
{CRYPT}.crypt($OPASS,frat-salt).\n);'`
Try changing it to this:
PASS=`perl -e 'print(userPassword:
I am attempting to write what I thought would be a simple wrapper
script around ldapmodify that would allow me to easily reset a user's
password. Inside my bash based wrapper script is a single line of perl
that encrypts the password I input and returns it as a specially formatted
string that then
