So, ok, rank...
The question, I imagine, is: how does rank help you understand how to get from
1 {"1 (3 5 5 #: i. 3 5 5)
to
(1&{@#:i.)3 5 5
But let's try that from another angle. Let's instead unfold the hook, giving us:
3 5 5 (1&{@#: i.) 3 5 5
Here, we can see just a bit more clearly
Raul -
So back to square One, totally different approach. (Most of this
again for my reference.)
I reviewed (x #: y) by the 'time' example
hms=. 24 60 60 & #:
hms 3600 1825 1201 930
1 0 0
0 30 25
0 20 1
0 15 30
Each atom on the right produces a list (3 items each in this case,
acco
Thanks Raul!
To me (#:) was an intellectual detour, but it works beautifully.
Bo.
Den 12:51 fredag den 10. juni 2016 skrev Raul Miller
:
Try this:
3 5 5 #: i. 3 5 5
Then try this:
1 {"1 (3 5 5 #: i. 3 5 5)
Then try this:
#:"#:
I hope that helps,
Thanks,
--
Raul
On Fri, Jun
Try this:
3 5 5 #: i. 3 5 5
Then try this:
1 {"1 (3 5 5 #: i. 3 5 5)
Then try this:
#:"#:
I hope that helps,
Thanks,
--
Raul
On Fri, Jun 10, 2016 at 6:38 AM, Martin Kreuzer wrote:
> Raul -
>
> Following this thread, I managed to grasp (reproduce) the expression (0 2 1
> |: 3 5 5 $
Raul -
Following this thread, I managed to grasp (reproduce) the expression
(0 2 1 |: 3 5 5 $ i. 5) which Bo found satisfactory.
Challenged by your remark "But probably no easier to read." I have
tried to sort of reconstruct your approach:
First I read up on dyadic Antibase (x #: y) and fou
