The gerund argument to @. must be all verbs
`(x"_) fixes the rightmost one
for the left one, the simplest way, you could enclose the operation with 4 : as
in
4 : '(] ` (x & mul) @. (2 | y)) mul~ x pow <. -: y'
On Monday, September 9, 2019, 12:49:39 p.m. EDT, Eugene Nonko
wrote:
Hello,
Hello,
I have this recursive dyad defined to calculate modular matrix exponential
by squaring:
pow =: 4 : 0
if. y = 1 do.
x
else.
(] ` (x & mul) @. (2 | y)) mul~ x pow <. -: y
end.
)
(mul verb can be defined to perform simple multiplication, then it will
work for regu
