Perhaps you should incorporate it in Bron's
http://www.jsoftware.com/jwiki/PrimitivePrimitives
R.E. Boss
> -Oorspronkelijk bericht-
> Van: [email protected]
> [mailto:[email protected]] Namens June Kim (???)
> Verzonden: vrijdag 31 august
On Fri, Aug 31, 2012 at 10:05 AM, R.E. Boss wrote:
> Perhaps you should incorporate it in Bron's
> http://www.jsoftware.com/jwiki/PrimitivePrimitives
You'd need a more complicated phrase there, something that supports a
higher rank y argument in (x e. y).
Ambrus
---
On Fri, Aug 31, 2012 at 8:20 AM, Zsbán Ambrus wrote:
> On Fri, Aug 31, 2012 at 10:05 AM, R.E. Boss wrote:
>> Perhaps you should incorporate it in Bron's
>> http://www.jsoftware.com/jwiki/PrimitivePrimitives
>
> You'd need a more complicated phrase there, something that supports a
> higher rank
I recently noticed this about " e. " but can't decide whether or not it's a bug:
0 e. i. 2 2
0
i. 2 2 NB. I'm pretty sure zero is in there...
0 1
2 3
0 e.~ i. 2 2
1 0
0 0
On Fri, Aug 31, 2012 at 8:20 AM, Zsbán Ambrus wrote:
> On Fri, Aug 31, 2012 at 10:05 AM, R.E. Boss wrote:
>> Pe
The elements of i. 2 2 are 0 1 and 2 3 .
Sent from my iPad
On Aug 31, 2012, at 8:38 AM, Devon McCormick wrote:
> I recently noticed this about " e. " but can't decide whether or not it's a
> bug:
>
> 0 e. i. 2 2
> 0
> i. 2 2 NB. I'm pretty sure zero is in there...
> 0 1
> 2 3
> 0 e
That's how it's supposed to work.
none of the items (well.. just one item) of 0 is an item of i.2 2
Try this:
boxitems=: <"_1
0 =/&boxitems i. 2 2
FYI,
--
Raul
On Fri, Aug 31, 2012 at 9:38 AM, Devon McCormick wrote:
> I recently noticed this about " e. " but can't decide whether or
This code produces a random point at integral values from 1 to 3. I would
like to chose a font and size and replace the "dot" with the letter A. Any
ideas?
load 'plot'
pd 'reset'
pd'aspect 1'
pd 'type line'
]P=:0 1 3 2 0{"1(4*|:#:i.4),.0
pd (<"1)P
pd 'type marker'
pd (<"1)1+?1 2$3
pd '
I guessed this made some sense I wasn't seeing, with the rank of " e.
" being _ rather than 1 as I thought.
0 1 e. i.2 2
1
On Fri, Aug 31, 2012 at 9:43 AM, Raul Miller wrote:
> That's how it's supposed to work.
>
> none of the items (well.. just one item) of 0 is an item of i.2 2
>
> Try thi
That x∊y in APL acts as if x∊,y is "original sin" from APL\360, and is an
obstacle to extending the definition of ⍳ (i. in J) to higher-ranked left
arguments.
In modelling e. you can not just apply <"_1 to both arguments. You can
apply <"r where r is <:#$y, but the left argument can have rank > 1
Oh, good point.
So... my =/&boxitems should have been:
demo=:4 :0
boxitems=. <"(<:#y)
x =/&boxitems y
)
0 demo i.2 2
Thanks,
--
Raul
On Fri, Aug 31, 2012 at 11:22 AM, Roger Hui wrote:
> That x∊y in APL acts as if x∊,y is "original sin" from APL\360, and is an
> obstacle to extendin
You want =/&:boxitems instead of =/&boxitems.
On Fri, Aug 31, 2012 at 10:14 AM, Raul Miller wrote:
> Oh, good point.
>
> So... my =/&boxitems should have been:
>
> demo=:4 :0
>boxitems=. <"(<:#y)
>x =/&boxitems y
> )
>
>0 demo i.2 2
>
> Thanks,
>
> --
> Raul
>
> On Fri, Aug 31, 201
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