I'm processing some big files on the order of 2G, extracting >= 250M of
data from
each. I have to memory map them to get the data:
readbigfile=: 3 : 0
JCHAR map_jmf_ 'f';y
NB. get data from f
unmap_jmf_'f'
)
I have about 150 of these files together with matching smaller ones, and
I need
Dear experts.
This program works correctly for scalar input.
FIFA=.[([:+/!*2^-@>:@])(+i.&>:)
2 FIFA 30.65625
It is the probability that the winning team of a soccermatch that ended 2-3, is
indeed the better of the two teams.
I want a table, but (i.11)FIFA/ i.11 doesn't do it. What is the work-a
How about this:
NB. I used extended integer to give rationals;
NB. I intended to show a compactly presented table,
NB. but Thunderbird seems to have spoilt it!
FIFA"0/~ i.5x
1r2 3r47r8 15r16 31r32
1r4 1r2 11r16 13r16 57r64
1r8 5r161r2 21r32 99r128
1r16 3r16 11r321r
When you want to see how J will proceed, you can set up an experiment,
and use echo to show what is happening when.
That said, your "0 verb will operate a box at a time (or a pair of
boxes at a time, since it's dyadic - the "0/ verb thus operating a
pair of boxes at a time but being monadic...).
Extending an example on composition from Sykes's LJ, I made the final step.
What's happening here?
A=:i.2 2
f=:<
g=:+/"1
f @ g A
--T-┐
│1│5│
L-+--
f & g A
--T-┐
│1│5│
L-+--
f"0 g A
--T-┐
│1│5│
L-+--
f @: g A
┐
│1 5│
L
f &: g A
┐
│1 5│
L
Here's the dialog:
A=:i.2 2
f=:<
g=:+/"1
f @ g A
f & g A
f"0 g A
f @: g A
f &: g A
f g A
(f g) A
h=: 13 :'f"0 g y'
h A
i=: 13 :'f g y'
i A
j=: 13 :'(f g)A'
j A
h
i
j
Linda
-Original Message-
From: [email protected]
[mailto:[email protected]
FIFA=.[([:+/!*2^-@>:@])(+i.&>:)
FIFA b. 0 NB. FIFA has infinite rank
_ _ _
+ b. 0 NB. You need rank 0
0 0 0
FIFA"0/~i.4xNB. the table
1r2 3r4 7r8 15r16
1r4 1r2 11r16 13r16
1r8 5r16 1r2 21r32
1r16 3r16 11r32 1r2
NB. FIFA_NAUGHT requires rank 0
NB.
I do not understand your question.
Are you asking why a hook is different from some other form of composition?
Thanks,
--
Raul
On Fri, Dec 25, 2015 at 7:45 AM, Linda A Alvord wrote:
> Extending an example on composition from Sykes's LJ, I made the final step.
> What's happening here?
>
>
>
I don't understand how
(f g) A
1 0
1 1
Where are the verbs f and g when you display the definition of I ?
Linda
What is it doing to make this result?
-Original Message-
From: [email protected]
[mailto:[email protected]] On Behalf Of R
I mean j (the message escaped when I was making a change)
j=: 13 :'(f g)A'
j
(2 2$1 0 1 1)"_
j A
1 0
1 1
-Original Message-
From: [email protected]
[mailto:[email protected]] On Behalf Of Linda A Alvord
Sent: Friday, December 25, 2
I found my mistake just then. A should be y. However, I still do not
understand how it gets the result shown:
j=: 13 :'(f g)y'
j
f g
j A
1 0
1 1
Linda
-Original Message-
From: [email protected]
[mailto:[email protected]] On Beha
Hi Linda,
j NB. Even though j returns f g, it is really (f g) which is a hook and is
not the same as f g A
f g
j=: 13 :'(f g)y'
f=:<
g=:+/"1
A=:i.2 2
j A
1 0
1 1
(f g) A
1 0
1 1
A f g A NB. (f g) n <=> n f (g n)
1 0
1 1
f g A NB. I am guessing that this is what you were
AHA Bob, I see the "logic" of it. F turns from "box" to "less than"
( Some days I see a fork in the road, but this wasn't one of them.)
Thanks, Linda
-Original Message-
From: [email protected]
[mailto:[email protected]] On Behalf Of rober
Thank you very much!- Bo
Den 15:07 fredag den 25. december 2015 skrev David Lambert
:
FIFA=.[([:+/!*2^-@>:@])(+i.&>:)
FIFA b. 0 NB. FIFA has infinite rank
_ _ _
+ b. 0 NB. You need rank 0
0 0 0
FIFA"0/~i.4x NB. the table
1r2 3r4 7r8 15r16
1r4 1
I've developed an adverb for working with large files:
http://code.jsoftware.com/wiki/NYCJUG/2014-05-13#Streaming_Through_Large_Files
. An example of using this code can be found here -
http://code.jsoftware.com/wiki/User:Devon_McCormick/Code/largeFileVet - and
the updated version of the code here
NB. Christmas
NB. To continue, please consult the code grid in the manual. Enter the
code at row 2978, column 3083.
n=:]+[:-:[:*/_2 _1++ NB. ROW n COL
REPEATS=: 2978 n 3083
START=: 20151125
PART1=: (33554393x|252533x*])^:(REPEATS-1)x:START
PART2=: 'finish the other 5!'
NB. Day 21
I had nearly the same for the last day. Then remembered that J has modular
exponentiation optimized. And I have 64-bit J, so no need for extended
numbers.
3 timex '(33554393&|@*&252533)^:(2947(<.&-:@(*:@+-3&*@[+]))3029)20151125'
5.12972
3 timex
'33554393|20151125*(33554393&|@^&(2947(<.&-:@(*
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